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Application of Calculus - Break-even Point

Grade 12ICSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Cost Function C(x)C(x): This function represents the total cost incurred by a company to produce xx units of a commodity. It is generally expressed as C(x)=F+V(x)C(x) = F + V(x), where FF is the fixed cost (overhead, rent) and V(x)V(x) is the variable cost (labor, materials). Visually, the fixed cost is the y-intercept of the cost curve, representing expenses even when production is zero.

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Revenue Function R(x)R(x): This represents the total money received from selling xx units at a price pp per unit, given by R(x)=pβ‹…xR(x) = p \cdot x. On a graph, the revenue function is typically a line or curve passing through the origin (0,0)(0,0), indicating that no units sold results in zero revenue.

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Profit Function P(x)P(x): The profit is the difference between total revenue and total cost, defined as P(x)=R(x)βˆ’C(x)P(x) = R(x) - C(x). Visually, profit is the vertical distance between the revenue curve and the cost curve when revenue is higher than cost.

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Break-even Point (BEP): The break-even point is the level of production xx where total revenue equals total cost (R(x)=C(x)R(x) = C(x)), resulting in zero profit (P(x)=0P(x) = 0). Geometrically, these are the points of intersection where the revenue curve and the cost curve meet.

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Profit and Loss Regions: On a break-even chart, the region where the Revenue curve stays above the Cost curve (R(x)>C(x)R(x) > C(x)) is the 'Profit Zone'. Conversely, the region where the Cost curve is above the Revenue curve (C(x)>R(x)C(x) > R(x)) is the 'Loss Zone'. The Break-even point acts as the boundary between these two states.

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Marginal Analysis: Calculus is used to find Marginal Cost MC=dCdxMC = \frac{dC}{dx} and Marginal Revenue MR=dRdxMR = \frac{dR}{dx}. While the break-even point tells us when we stop losing money, the maximum profit occurs at a production level where MR=MCMR = MC and the second derivative of profit is negative.

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Average Cost and Break-even: The Average Cost is defined as AC=C(x)xAC = \frac{C(x)}{x}. A business breaks even when the selling price pp is equal to the Average Cost, because p=C(x)xβ€…β€ŠβŸΉβ€…β€Špx=C(x)p = \frac{C(x)}{x} \implies px = C(x), which is the break-even condition.

πŸ“Formulae

Total Cost: C(x)=F+V(x)C(x) = F + V(x)

Total Revenue: R(x)=pΓ—xR(x) = p \times x

Profit Function: P(x)=R(x)βˆ’C(x)P(x) = R(x) - C(x)

Break-even Condition: R(x)=C(x)R(x) = C(x) or P(x)=0P(x) = 0

Marginal Cost: MC=ddxC(x)MC = \frac{d}{dx} C(x)

Marginal Revenue: MR=ddxR(x)MR = \frac{d}{dx} R(x)

Average Cost: AC=C(x)xAC = \frac{C(x)}{x}

πŸ’‘Examples

Problem 1:

A manufacturer's total cost function is given by C(x)=300x+5000C(x) = 300x + 5000 and the revenue function is R(x)=500xR(x) = 500x. Find the break-even point.

Solution:

  1. Set the Revenue function equal to the Cost function for break-even: R(x)=C(x)R(x) = C(x)
  2. Substitute the given expressions: 500x=300x+5000500x = 300x + 5000
  3. Rearrange the equation to solve for xx: 500xβˆ’300x=5000500x - 300x = 5000
  4. Simplify: 200x=5000200x = 5000
  5. Calculate xx: x=5000200=25x = \frac{5000}{200} = 25 units.

Explanation:

To find the break-even point, we identify the volume of sales where total income matches total expenditure. Solving the linear equation gives the specific number of units needed to reach zero profit.

Problem 2:

The cost function for a product is C(x)=15+2xC(x) = 15 + 2x and the demand function is p=10βˆ’xp = 10 - x. Find the break-even points.

Solution:

  1. First, determine the Revenue function R(x)R(x): R(x)=pβ‹…x=(10βˆ’x)x=10xβˆ’x2R(x) = p \cdot x = (10 - x)x = 10x - x^2
  2. Set R(x)=C(x)R(x) = C(x) for break-even: 10xβˆ’x2=15+2x10x - x^2 = 15 + 2x
  3. Rearrange into a standard quadratic equation form: x2βˆ’8x+15=0x^2 - 8x + 15 = 0
  4. Factorize the quadratic equation: (xβˆ’3)(xβˆ’5)=0(x - 3)(x - 5) = 0
  5. Solve for xx: x=3Β orΒ x=5x = 3 \text{ or } x = 5

Explanation:

In cases with non-linear demand, there can be multiple break-even points. Here, the company breaks even at 3 units and again at 5 units. Between these two values, the company makes a profit because the quadratic revenue is higher than the linear cost.