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Algebra - Matrices: Concept, Types, Transpose, Symmetric and Skew-symmetric matrices

Grade 12ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Definition and Order: A matrix is an ordered rectangular array of numbers or functions. The numbers are called elements or entries. A matrix having mm rows and nn columns is called a matrix of order m×nm \times n. Visually, the order represents the 'dimensions' of the grid, where mm is the vertical count and nn is the horizontal count.

Types of Matrices: A Row Matrix has only one horizontal row [a11a12...a1n][a_{11} a_{12} ... a_{1n}], while a Column Matrix has only one vertical column. A Square Matrix has an equal number of rows and columns (m=nm = n). A Zero or Null Matrix is one where every element is 00, visually appearing as an empty grid of zeros.

Diagonal and Identity Matrices: A Diagonal Matrix is a square matrix where all non-diagonal elements are zero. An Identity Matrix (II) is a diagonal matrix where all diagonal elements are 11. Visually, the Identity matrix shows a 'strip' of ones running from the top-left corner to the bottom-right corner, with all other spaces filled by zeros.

Transpose of a Matrix: The transpose of a matrix AA, denoted by ATA^T or AA', is formed by interchanging its rows and columns. If AA is of order m×nm \times n, then ATA^T is of order n×mn \times m. Visually, this is like rotating the matrix over its main diagonal axis so that the first row becomes the first column.

Symmetric Matrix: A square matrix AA is said to be symmetric if AT=AA^T = A. This means the element at aija_{ij} is equal to the element at ajia_{ji}. Visually, if you fold the matrix along its main diagonal, the elements on both sides match perfectly like a mirror image.

Skew-Symmetric Matrix: A square matrix AA is said to be skew-symmetric if AT=AA^T = -A. This implies aij=ajia_{ij} = -a_{ji} for all i,ji, j. Crucially, all diagonal elements of a skew-symmetric matrix must be zero (aii=0a_{ii} = 0). Visually, the diagonal is a line of zeros, and the elements across the diagonal are identical in magnitude but opposite in sign.

📐Formulae

General form: A=[aij]m×nA = [a_{ij}]_{m \times n}

Transpose property: (AT)T=A(A^T)^T = A

Transpose of sum: (A+B)T=AT+BT(A + B)^T = A^T + B^T

Transpose of product: (AB)T=BTAT(AB)^T = B^T A^T

Symmetric condition: aij=ajia_{ij} = a_{ji} for all i,ji, j

Skew-Symmetric condition: aij=ajia_{ij} = -a_{ji} and aii=0a_{ii} = 0

Decomposition Theorem: Any square matrix AA can be expressed as A=12(A+AT)+12(AAT)A = \frac{1}{2}(A + A^T) + \frac{1}{2}(A - A^T), where 12(A+AT)\frac{1}{2}(A + A^T) is symmetric and 12(AAT)\frac{1}{2}(A - A^T) is skew-symmetric.

💡Examples

Problem 1:

Given the matrix A=[2456]A = \begin{bmatrix} 2 & 4 \\ 5 & 6 \end{bmatrix}, find ATA^T and verify if A+ATA + A^T is symmetric.

Solution:

Step 1: Find the transpose ATA^T by swapping rows and columns: AT=[2546]A^T = \begin{bmatrix} 2 & 5 \\ 4 & 6 \end{bmatrix} Step 2: Calculate B=A+ATB = A + A^T: B=[2456]+[2546]=[2+24+55+46+6]=[49912]B = \begin{bmatrix} 2 & 4 \\ 5 & 6 \end{bmatrix} + \begin{bmatrix} 2 & 5 \\ 4 & 6 \end{bmatrix} = \begin{bmatrix} 2+2 & 4+5 \\ 5+4 & 6+6 \end{bmatrix} = \begin{bmatrix} 4 & 9 \\ 9 & 12 \end{bmatrix} Step 3: Check if BB is symmetric by finding BTB^T: BT=[49912]B^T = \begin{bmatrix} 4 & 9 \\ 9 & 12 \end{bmatrix} Since BT=BB^T = B, the matrix A+ATA + A^T is symmetric.

Explanation:

This example demonstrates the construction of the transpose and proves the theorem that the sum of a matrix and its transpose always results in a symmetric matrix.

Problem 2:

Show that the matrix B=[023205350]B = \begin{bmatrix} 0 & 2 & -3 \\ -2 & 0 & 5 \\ 3 & -5 & 0 \end{bmatrix} is skew-symmetric.

Solution:

Step 1: Find the transpose BTB^T: BT=[023205350]B^T = \begin{bmatrix} 0 & -2 & 3 \\ 2 & 0 & -5 \\ -3 & 5 & 0 \end{bmatrix} Step 2: Find B-B by multiplying every element of BB by 1-1: B=[(0)(2)(3)(2)(0)(5)(3)(5)(0)]=[023205350]-B = \begin{bmatrix} -(0) & -(2) & -(-3) \\ -(-2) & -(0) & -(5) \\ -(3) & -(-5) & -(0) \end{bmatrix} = \begin{bmatrix} 0 & -2 & 3 \\ 2 & 0 & -5 \\ -3 & 5 & 0 \end{bmatrix} Step 3: Compare BTB^T and B-B. Since BT=BB^T = -B and all diagonal elements are 00, the matrix BB is skew-symmetric.

Explanation:

To verify a skew-symmetric matrix, we check if the transpose equals the negative of the original matrix and ensure the main diagonal consists of zeros.