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Algebra - Determinants: Properties, Minors, Co-factors

Grade 12ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A Determinant is a scalar value associated with a square matrix, represented visually as a square array of numbers enclosed between two vertical bars, such as A=abcd|A| = \begin{vmatrix} a & b \\ c & d \end{vmatrix}. Unlike matrices, a determinant must always have an equal number of rows and columns (n×nn \times n).

The Minor (MijM_{ij}) of an element aija_{ij} is the determinant obtained by deleting the ithi^{th} row and jthj^{th} column in which the element aija_{ij} lies. Visually, if you cross out the horizontal and vertical lines intersecting at aija_{ij}, the remaining elements form the sub-matrix for the minor.

The Co-factor (AijA_{ij} or CijC_{ij}) is the signed version of the minor, calculated as Aij=(1)i+jMijA_{ij} = (-1)^{i+j} M_{ij}. The signs follow a checkerboard pattern across the determinant grid, starting with a ++ sign at the top-left corner (a11)(a_{11}) and alternating signs for adjacent elements.

Expansion of a Determinant can be performed along any row or any column. The value of the determinant is the sum of the products of elements of any row (or column) with their corresponding co-factors. For a 3×33 \times 3 determinant, this is often visualized as taking the top row elements and multiplying them by the 2×22 \times 2 determinants that remain after blocking their respective rows and columns.

Property of Identical Rows/Columns: If any two rows or columns of a determinant are identical or proportional, the value of the determinant is zero. Visually, if you see two horizontal lines of numbers that are exactly the same, you can immediately conclude A=0|A| = 0.

Scalar Multiplication Property: If every element of a row (or a column) of a determinant is multiplied by a constant kk, then the value of the determinant gets multiplied by kk. This differs from matrices where a scalar multiplies every single element; in determinants, it only affects one row or column at a time.

Property of Invariance: The value of a determinant remains unchanged if we add a multiple of one row to another row (or one column to another column), denoted as RiRi+kRjR_i \rightarrow R_i + kR_j or CiCi+kCjC_i \rightarrow C_i + kC_j. This allows for simplifying complex determinants into upper triangular forms where most elements below the diagonal are zero.

Area of a Triangle: Determinants provide a visual geometric application to find the area of a triangle with vertices (x1,y1)(x_1, y_1), (x2,y2)(x_2, y_2), and (x3,y3)(x_3, y_3). If the calculated determinant value is zero, it indicates that the three points are collinear (lying on a single straight line).

📐Formulae

Value of 2×22 \times 2 determinant: a11a12a21a22=a11a22a12a21\begin{vmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{vmatrix} = a_{11}a_{22} - a_{12}a_{21}

Co-factor Formula: Aij=(1)i+jMijA_{ij} = (-1)^{i+j} M_{ij}

Determinant Expansion (Row 1): A=a11A11+a12A12+a13A13|A| = a_{11}A_{11} + a_{12}A_{12} + a_{13}A_{13}

Property of Transpose: A=AT|A| = |A^T| (The determinant of a matrix and its transpose are equal)

Scalar property for n×nn \times n matrix: kA=knA|kA| = k^n |A| where nn is the order of the matrix

Area of a Triangle: Area=12x1y11x2y21x3y31Area = \frac{1}{2} |\begin{vmatrix} x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1 \end{vmatrix}|

💡Examples

Problem 1:

Find the minor and co-factor of the element a21a_{21} in the determinant Δ=123456789\Delta = \begin{vmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{vmatrix}.

Solution:

  1. Identify the position: a21a_{21} is the element in the 2nd row and 1st column, which is 44.
  2. Find the Minor M21M_{21}: Delete the 2nd row and 1st column. M21=2389=(2×9)(3×8)=1824=6M_{21} = \begin{vmatrix} 2 & 3 \\ 8 & 9 \end{vmatrix} = (2 \times 9) - (3 \times 8) = 18 - 24 = -6.
  3. Find the Co-factor A21A_{21}: Use the formula Aij=(1)i+jMijA_{ij} = (-1)^{i+j} M_{ij}. A21=(1)2+1M21=(1)3(6)=(1)(6)=6A_{21} = (-1)^{2+1} M_{21} = (-1)^3 (-6) = (-1)(-6) = 6.

Explanation:

To find the minor, we isolate the sub-determinant by removing the row and column containing the target element. The co-factor then applies the appropriate sign based on the row/column index sum.

Problem 2:

Evaluate the determinant Δ=10218361341736\Delta = \begin{vmatrix} 102 & 18 & 36 \\ 1 & 3 & 4 \\ 17 & 3 & 6 \end{vmatrix} using properties.

Solution:

  1. Look for common factors in Row 1: Notice that 102=6×17102 = 6 \times 17, 18=6×318 = 6 \times 3, and 36=6×636 = 6 \times 6.
  2. Take out factor 66 from R1R_1: Δ=617361341736\Delta = 6 \begin{vmatrix} 17 & 3 & 6 \\ 1 & 3 & 4 \\ 17 & 3 & 6 \end{vmatrix}.
  3. Compare rows: Observe that Row 1 (R1R_1) and Row 3 (R3R_3) are now identical.
  4. Apply Property: Since two rows are identical, the value of the determinant is 00. Δ=6×0=0\Delta = 6 \times 0 = 0.

Explanation:

By identifying a common factor and applying the property that a determinant with two identical rows is zero, we avoid tedious calculations involved in standard expansion.