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Number and Algebra - Sequences and Series (Arithmetic & Geometric)

Grade 12IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Arithmetic Sequences (Linear Growth): An arithmetic sequence is a pattern where the difference between consecutive terms is constant, known as the common difference dd. Visually, if you plot the term number nn on the x-axis and the term value unu_n on the y-axis, the points will form a discrete straight line. The gradient of this line corresponds to dd, and the sequence is increasing if d>0d > 0 and decreasing if d<0d < 0.

Geometric Sequences (Exponential Change): In a geometric sequence, each term is found by multiplying the previous term by a constant called the common ratio rr. This results in exponential growth if r>1r > 1 or exponential decay if 0<r<10 < r < 1. Visually, these sequences form a curve that either accelerates away from the x-axis or flattens out towards it. If rr is negative, the terms will alternate between positive and negative values, creating a zig-zag visual pattern above and below the horizontal axis.

Sigma Notation (Summation): The symbol \sum is used to represent the sum of a sequence of numbers. The expression k=1nuk\sum_{k=1}^{n} u_k indicates that you should substitute integers from the lower limit 11 to the upper limit nn into the general term uku_k and add the results together. Visually, this can be represented as the total area of a series of rectangles where the width is 1 and the height is the value of each term.

Convergence of Geometric Series: A geometric series is said to converge if the sum of its terms approaches a finite limit as the number of terms goes to infinity. This only occurs when the absolute value of the common ratio is less than one (r<1|r| < 1). On a graph of the partial sums SnS_n vs nn, a convergent series will appear to level off toward a horizontal asymptote, which represents the sum to infinity SS_{\infty}.

Arithmetic Series and Partial Sums: An arithmetic series is the sum of the terms in an arithmetic sequence. The formula for the sum Sn=n2(u1+un)S_n = \frac{n}{2}(u_1 + u_n) can be visualized as finding the area of a trapezoid, where nn is the height and the two parallel sides are the first and last terms. As nn increases, the sum of an arithmetic sequence grows quadratically.

Applications to Finance: Many financial models are based on sequences. Simple interest and linear depreciation follow arithmetic patterns (linear growth/decay). In contrast, compound interest and reducing balance depreciation follow geometric patterns (exponential growth/decay), where the value changes by a fixed percentage each period. This can be visualized by comparing a straight line (simple interest) to a curve that grows steeper over time (compound interest).

📐Formulae

un=u1+(n1)du_n = u_1 + (n-1)d

Sn=n2(2u1+(n1)d)S_n = \frac{n}{2}(2u_1 + (n-1)d)

Sn=n2(u1+un)S_n = \frac{n}{2}(u_1 + u_n)

un=u1rn1u_n = u_1 r^{n-1}

Sn=u1(rn1)r1=u1(1rn)1r,r1S_n = \frac{u_1(r^n - 1)}{r - 1} = \frac{u_1(1 - r^n)}{1 - r}, r \neq 1

S=u11r,r<1S_{\infty} = \frac{u_1}{1 - r}, |r| < 1

💡Examples

Problem 1:

An arithmetic sequence has a first term u1=7u_1 = 7 and a common difference d=3d = 3. Find the value of the 20th term and the sum of the first 20 terms.

Solution:

  1. To find the 20th term (u20u_{20}), use the formula un=u1+(n1)du_n = u_1 + (n-1)d: u20=7+(201)(3)=7+19(3)=7+57=64u_{20} = 7 + (20-1)(3) = 7 + 19(3) = 7 + 57 = 64.

  2. To find the sum of the first 20 terms (S20S_{20}), use the formula Sn=n2(u1+un)S_n = \frac{n}{2}(u_1 + u_n): S20=202(7+64)=10(71)=710S_{20} = \frac{20}{2}(7 + 64) = 10(71) = 710.

Explanation:

This problem demonstrates the basic application of arithmetic formulas. First, we identify the specific term using the general term formula, then we use that result to calculate the sum of the series efficiently.

Problem 2:

In a geometric sequence, the second term is 12 and the fifth term is 324. Calculate the common ratio rr, the first term u1u_1, and determine the sum of the first 5 terms.

Solution:

  1. Set up equations using un=u1rn1u_n = u_1 r^{n-1}: u2=u1r1=12u_2 = u_1 r^1 = 12 u5=u1r4=324u_5 = u_1 r^4 = 324

  2. Divide the second equation by the first to eliminate u1u_1: u1r4u1r1=32412    r3=27    r=273=3\frac{u_1 r^4}{u_1 r^1} = \frac{324}{12} \implies r^3 = 27 \implies r = \sqrt[3]{27} = 3.

  3. Substitute rr back to find u1u_1: u1(3)=12    u1=4u_1(3) = 12 \implies u_1 = 4.

  4. Calculate the sum S5S_5 using Sn=u1(rn1)r1S_n = \frac{u_1(r^n - 1)}{r - 1}: S5=4(351)31=4(2431)2=2(242)=484S_5 = \frac{4(3^5 - 1)}{3 - 1} = \frac{4(243 - 1)}{2} = 2(242) = 484.

Explanation:

For geometric sequences where the first term is not given, we solve a system of equations by dividing the terms to isolate the common ratio rr. Once the parameters are known, the sum formula is applied.