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Geometry and Trigonometry - The Unit Circle and Radian Measure

Grade 12IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Radian Measure: A radian is the angle subtended at the center of a circle by an arc whose length is equal to the radius of the circle. Visually, imagine taking the radius of a circle and wrapping it along the edge; the angle formed is 11 radian. Because the total circumference is 2πr2\pi r, a full rotation of 360360^\circ is equal to 2π2\pi radians.

The Unit Circle: This is a circle with a radius of r=1r = 1 centered at the origin (0,0)(0,0) in the Cartesian plane. For any point P(x,y)P(x, y) on the circle making an angle θ\theta with the positive x-axis, the coordinates are defined as x=cosθx = \cos \theta and y=sinθy = \sin \theta. Visually, the cosine represents the horizontal displacement from the y-axis, and the sine represents the vertical displacement from the x-axis.

Arc Length and Sector Area: When an angle θ\theta is measured in radians, the calculations for circles are simplified. The arc length ss is the distance along the curved edge of the sector, and the sector area AA is the space enclosed by the two radii and the arc. Visually, a sector is like a slice of pie where the crust length is the arc length.

Quadrant Signs (ASTC): The signs of trigonometric ratios depend on which quadrant the terminal side of the angle θ\theta lies in. In Quadrant I (top-right), all ratios are positive. In Quadrant II (top-left), only sinθ\sin \theta is positive. In Quadrant III (bottom-left), only tanθ\tan \theta is positive. In Quadrant IV (bottom-right), only cosθ\cos \theta is positive. This 'All Students Take Calculus' rule follows from the positive/negative signs of xx and yy coordinates on the unit circle.

Exact Values and Reference Angles: For any angle θ\theta, the reference angle θref\theta_{ref} is the acute angle formed between the terminal side and the x-axis. Visually, if an angle is in the second quadrant, its reference angle is πθ\pi - \theta. This allows us to use exact values from the first quadrant (like π6,π4,π3\frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3}) to find values for larger angles by applying the appropriate quadrant sign.

The Pythagorean Identity: For any point on the unit circle, the relationship between sine and cosine is governed by the equation of the circle x2+y2=1x^2 + y^2 = 1. Substituting the trig ratios gives the fundamental identity cos2θ+sin2θ=1\cos^2 \theta + \sin^2 \theta = 1. Visually, this is simply the Pythagorean theorem applied to a right-angled triangle with hypotenuse 11 inside the unit circle.

Tangent Ratio: On the unit circle, tanθ\tan \theta is defined as the ratio of the y-coordinate to the x-coordinate, or sinθcosθ\frac{\sin \theta}{\cos \theta}. Geometrically, if you draw a tangent line to the circle at the point (1,0)(1, 0), the value of tanθ\tan \theta corresponds to the y-intercept of the line formed by the terminal side of the angle intersecting this tangent line.

📐Formulae

Degrees to Radians: θrad=θdeg×π180\theta_{rad} = \theta_{deg} \times \frac{\pi}{180}

Radians to Degrees: θdeg=θrad×180π\theta_{deg} = \theta_{rad} \times \frac{180}{\pi}

Arc Length: s=rθs = r\theta (where θ\theta is in radians)

Area of a Sector: A=12r2θA = \frac{1}{2}r^2\theta (where θ\theta is in radians)

Coordinates on Unit Circle: (x,y)=(cosθ,sinθ)(x, y) = (\cos \theta, \sin \theta)

Tangent Identity: tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}

Pythagorean Identity: sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

💡Examples

Problem 1:

A sector of a circle has a radius of 8 cm8 \text{ cm} and an arc length of 12 cm12 \text{ cm}. Find the angle of the sector in radians and calculate the area of the sector.

Solution:

Step 1: Use the arc length formula s=rθs = r\theta to find the angle. 12=8×θ    θ=128=1.5 radians12 = 8 \times \theta \implies \theta = \frac{12}{8} = 1.5 \text{ radians} Step 2: Use the sector area formula A=12r2θA = \frac{1}{2}r^2\theta with the calculated angle. A=12×(8)2×1.5A = \frac{1}{2} \times (8)^2 \times 1.5 A=12×64×1.5=32×1.5=48 cm2A = \frac{1}{2} \times 64 \times 1.5 = 32 \times 1.5 = 48 \text{ cm}^2

Explanation:

We first isolate the unknown angle using the relationship between radius and arc length. Once the angle is known in radians, it can be directly substituted into the area formula.

Problem 2:

Given that cosθ=513\cos \theta = -\frac{5}{13} and π<θ<3π2\pi < \theta < \frac{3\pi}{2}, find the exact value of sinθ\sin \theta and tanθ\tan \theta.

Solution:

Step 1: Identify the quadrant. The interval π<θ<3π2\pi < \theta < \frac{3\pi}{2} indicates the angle is in Quadrant III, where both sine and cosine are negative, but tangent is positive. Step 2: Use the Pythagorean identity sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 to find sinθ\sin \theta. sin2θ+(513)2=1\sin^2 \theta + (-\frac{5}{13})^2 = 1 sin2θ+25169=1\sin^2 \theta + \frac{25}{169} = 1 sin2θ=125169=144169\sin^2 \theta = 1 - \frac{25}{169} = \frac{144}{169} sinθ=±144169=±1213\sin \theta = \pm \sqrt{\frac{144}{169}} = \pm \frac{12}{13} Since θ\theta is in Quadrant III, sinθ=1213\sin \theta = -\frac{12}{13}. Step 3: Calculate tanθ\tan \theta. tanθ=sinθcosθ=12/135/13=125\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{-12/13}{-5/13} = \frac{12}{5}

Explanation:

We use the Pythagorean identity to find the magnitude of the missing sine ratio. The specific quadrant information is then used to determine whether the result should be positive or negative.