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Geometry and Trigonometry - Graphs of Trigonometric Functions

Grade 12IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

General Sinusoidal Model: The functions y=asin(b(xc))+dy = a \\sin(b(x - c)) + d and y=acos(b(xc))+dy = a \\cos(b(x - c)) + d represent periodic waves. Visually, the sine graph starts at the midline (0,d)(0, d) and moves upwards (if a>0a > 0), while the cosine graph starts at its maximum value (0,a+d)(0, a + d). Both functions oscillate infinitely between a maximum and a minimum value.

Amplitude (a|a|): This is the vertical stretch factor. Visually, it represents half the vertical distance between the peak (maximum) and the trough (minimum), or the distance from the horizontal midline to either the max or min. A negative aa indicates a vertical reflection across the midline.

Period and Horizontal Frequency (bb): The period is the horizontal length of one complete cycle. It is calculated as P=frac2pibP = \\frac{2\\pi}{|b|} for sine and cosine. Visually, as b|b| increases, the graph undergoes horizontal compression, meaning the waves appear more frequently over a fixed interval.

Phase Shift (cc): This is the horizontal translation of the function. In the expression (xc)(x - c), a positive cc value shifts the graph to the right, while a negative cc value shifts it to the left. For a cosine graph, the phase shift often identifies the xx-coordinate of the first maximum point.

Midline and Vertical Shift (dd): The constant dd shifts the graph vertically. The horizontal line y=dy = d is called the midline or principal axis. The graph is perfectly symmetrical above and below this line. The maximum value is d+ad + |a| and the minimum is dad - |a|.

The Tangent Function: The graph of y=atan(b(xc))+dy = a \\tan(b(x - c)) + d differs significantly from sine and cosine. It does not have an amplitude because the range is (infty,infty)(-\\infty, \\infty). Visually, it consists of a series of repeating 'S-curves' separated by vertical asymptotes where the function is undefined, occurring at x=fracpi2bx = \\frac{\\pi}{2b} for the basic function y=tan(bx)y = \\tan(bx).

Domain and Range: For y=asin(bx)y = a \\sin(bx) or y=acos(bx)y = a \\cos(bx), the domain is all real numbers (mathbbR)(\\mathbb{R}) and the range is [da,d+a][d - |a|, d + |a|]. For y=tan(x)y = \\tan(x), the domain excludes values where cos(x)=0\\cos(x) = 0 (the asymptotes), and the range is all real numbers.

Transformations of Trig Graphs: To map f(x)f(x) to g(x)=af(b(xc))+dg(x) = a f(b(x - c)) + d, apply transformations in this order: 1. Horizontal stretch/compression by factor frac1b\\frac{1}{b}, 2. Vertical stretch by factor aa, 3. Reflection (if aa or bb are negative), 4. Horizontal translation by cc, 5. Vertical translation by dd.

📐Formulae

y=asin(b(xc))+dy = a \\sin(b(x - c)) + d

y=acos(b(xc))+dy = a \\cos(b(x - c)) + d

Amplitude(A)=fracymaxymin2Amplitude (A) = \\frac{y_{max} - y_{min}}{2}

VerticalShift(d)=fracymax+ymin2Vertical Shift (d) = \\frac{y_{max} + y_{min}}{2}

Period(P)=frac2pibtext(forsineandcosine)Period (P) = \\frac{2\\pi}{b} \\text{ (for sine and cosine)}

Period(P)=fracpibtext(fortangent)Period (P) = \\frac{\\pi}{b} \\text{ (for tangent)}

b=frac2piPeriodb = \\frac{2\\pi}{Period}

textRangeforsine/cosine:[da,d+a]\\text{Range for sine/cosine: } [d - |a|, d + |a|]

💡Examples

Problem 1:

A periodic function is modeled by f(x)=acos(b(xc))+df(x) = a \\cos(b(x - c)) + d. The graph has a maximum point at (3,12)(3, 12) and the next minimum point occurs at (9,2)(9, 2). Determine the values of a,b,c,a, b, c, and dd.

Solution:

  1. Find dd (Midline): d=frac12+22=7d = \\frac{12 + 2}{2} = 7. \n2. Find aa (Amplitude): a=frac1222=5a = \\frac{12 - 2}{2} = 5. \n3. Find the Period (PP): The distance between a max and the next min is half a period. So, frac12P=93=6\\frac{1}{2}P = 9 - 3 = 6, which means P=12P = 12. \n4. Find bb: b=frac2piP=frac2pi12=fracpi6b = \\frac{2\\pi}{P} = \\frac{2\\pi}{12} = \\frac{\\pi}{6}. \n5. Find cc (Phase Shift): Since it is a cosine graph and the first maximum is at x=3x = 3, we set c=3c = 3. \nResulting equation: f(x)=5cos(fracpi6(x3))+7f(x) = 5 \\cos(\\frac{\\pi}{6}(x - 3)) + 7.

Explanation:

We use the vertical extremes to find the midline and amplitude. The horizontal distance between consecutive extrema gives half the period, and the location of the maximum provides the phase shift for a cosine model.

Problem 2:

State the transformations required to map the graph of y=sin(x)y = \\sin(x) onto y=3sin(2x+fracpi2)+4y = -3 \\sin(2x + \\frac{\\pi}{2}) + 4.

Solution:

  1. Rewrite the function in the form asin(b(xc))+da \\sin(b(x - c)) + d: y=3sin(2(x+fracpi4))+4y = -3 \\sin(2(x + \\frac{\\pi}{4})) + 4. \n2. Vertical Stretch: A vertical stretch by a scale factor of 3. \n3. Reflection: A reflection in the x-axis (due to the negative sign). \n4. Horizontal Compression: A horizontal compression by a scale factor of frac12\\frac{1}{2} (since b=2b=2). \n5. Horizontal Translation: A shift of fracpi4\\frac{\\pi}{4} units to the left. \n6. Vertical Translation: A shift of 4 units upwards.

Explanation:

First, factor out the coefficient of xx to correctly identify the phase shift. Then, list the transformations by analyzing the parameters a,b,c,a, b, c, and dd sequentially.