Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Definition of a Function: A relation where every input in the domain maps to exactly one output in the range. Visually, a function must pass the Vertical Line Test, meaning any vertical line drawn through the graph intersects the curve at most once.
Domain and Range: The domain is the set of all possible input values (-axis coverage), and the range is the set of all possible output values (-axis coverage). On a graph, you can identify the domain by looking at the left-to-right span and the range by looking at the bottom-to-top span of the curve.
Composite Functions: Formed by substituting one function into another, denoted as . This represents a sequence of transformations where the output of the inner function becomes the input for the outer function . For the composite to exist, the range of must be a subset of the domain of .
Inverse Functions: An inverse function reverses the operation of . A function has an inverse only if it is one-to-one (bijective), which is verified visually using the Horizontal Line Test: a horizontal line should only touch the graph once.
Geometric Properties of Inverses: The graph of an inverse function is a reflection of the original function across the line . If a point lies on the graph of , then the point must lie on the graph of .
Domain Restrictions: Functions that are not naturally one-to-one, such as , require a domain restriction (e.g., ) to have an inverse. Visually, this involves selecting only one 'branch' of a curve (like the right side of a parabola) so it passes the Horizontal Line Test.
Self-Inverse Functions: Some functions are their own inverse, meaning . A common visual example is the reciprocal function , which is symmetrical about the line and .
📐Formulae
💡Examples
Problem 1:
Given , where , find the expression for and state its domain.
Solution:
- Let .\n2. Swap and to find the inverse: .\n3. Multiply both sides by : .\n4. Expand the bracket: .\n5. Move terms with to one side: .\n6. Factor out : .\n7. Solve for : or .\n8. Therefore, .\n9. The domain of is all real numbers except where the denominator is zero: .
Explanation:
To find an inverse, we swap the roles of and and solve for the new . The domain of the inverse is restricted by the vertical asymptote of the resulting expression, which corresponds to the horizontal asymptote of the original function.
Problem 2:
Let and . Find and solve for when .
Solution:
- Substitute into : .\n2. Expand the squared binomial: .\n3. Simplify: .\n4. Set the equation to zero: .\n5. Divide by 4: .\n6. Factor the quadratic: .\n7. Find the roots: and .
Explanation:
Composite functions involve nesting the 'inner' function inside the 'outer' function. Once the expression is simplified, standard algebraic techniques like factoring are used to find the roots.