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Matrices - Concept, notation, order, equality, types of matrices, zero and identity matrix

Grade 12CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A matrix is an ordered rectangular array of numbers or functions. These numbers or functions are called the elements or entries of the matrix. We denote matrices by capital letters such as A,B,CA, B, C. Visually, a matrix is represented as a grid of values enclosed within square brackets [][ ] or parentheses ()( ), arranged in horizontal rows and vertical columns.

The order of a matrix indicates its dimensions. A matrix having mm rows and nn columns is said to be of order m×nm \times n (read as mm by nn). If a matrix is of order 3×23 \times 2, it visually appears as a tall rectangle with 3 horizontal layers and 2 vertical stacks, containing a total of 3×2=63 \times 2 = 6 elements.

Two matrices A=[aij]A = [a_{ij}] and B=[bij]B = [b_{ij}] are said to be equal if they are of the same order and each element of AA is equal to the corresponding element of BB (aij=bija_{ij} = b_{ij} for all ii and jj). Visually, equality means that if you overlay one matrix on top of the other, every single number in the grid matches its counterpart perfectly.

A Row Matrix is a matrix that has only one row, represented as [a11a12...a1n][a_{11} \, a_{12} \, ... \, a_{1n}] with order 1×n1 \times n. It looks like a single horizontal strip of numbers. A Column Matrix has only one column, represented as a vertical stack of numbers with order m×1m \times 1.

A Square Matrix is a matrix where the number of rows is equal to the number of columns (m=nm = n). In a square matrix, the elements a11,a22,...,anna_{11}, a_{22}, ..., a_{nn} are called the diagonal elements. Visually, these elements form a straight line from the top-left corner to the bottom-right corner, known as the principal diagonal.

A Diagonal Matrix is a square matrix where all non-diagonal elements are zero. A Scalar Matrix is a diagonal matrix where all diagonal elements are equal to a constant kk. An Identity Matrix is a special scalar matrix where all diagonal elements are 11 and all others are 00, denoted by II. Visually, an identity matrix looks like a grid of zeros with a diagonal 'slash' of ones through the center.

A Zero Matrix or Null Matrix is a matrix in which all elements are zero. It is denoted by OO. Unlike identity matrices, zero matrices do not have to be square and can be of any order m×nm \times n. Visually, it is simply a rectangular block filled entirely with zeros.

📐Formulae

A=[aij]m×nA = [a_{ij}]_{m \times n} where 1im1 \le i \le m (rows) and 1jn1 \le j \le n (columns)

Total number of elements in a matrix of order m×n=mnm \times n = mn

Equality: A=B    (orderA=orderB)(aij=biji,j)A = B \iff (order \, A = order \, B) \land (a_{ij} = b_{ij} \, \forall \, i, j)

Diagonal Matrix: aij=0a_{ij} = 0 when iji \neq j

Identity Matrix In=[aij]n×nI_n = [a_{ij}]_{n \times n} where aij=1a_{ij} = 1 if i=ji = j and aij=0a_{ij} = 0 if iji \neq j

Scalar Matrix: aij=ka_{ij} = k if i=ji = j and aij=0a_{ij} = 0 if iji \neq j

💡Examples

Problem 1:

Construct a 3×23 \times 2 matrix A=[aij]A = [a_{ij}] whose elements are given by aij=12i3ja_{ij} = \frac{1}{2}|i - 3j|.

Solution:

  1. The matrix AA has order 3×23 \times 2, so it has 3 rows (i=1,2,3i=1, 2, 3) and 2 columns (j=1,2j=1, 2).
  2. Calculate each element:
  • a11=1213(1)=122=1a_{11} = \frac{1}{2}|1 - 3(1)| = \frac{1}{2}|-2| = 1
  • a12=1213(2)=125=2.5a_{12} = \frac{1}{2}|1 - 3(2)| = \frac{1}{2}|-5| = 2.5
  • a21=1223(1)=121=0.5a_{21} = \frac{1}{2}|2 - 3(1)| = \frac{1}{2}|-1| = 0.5
  • a22=1223(2)=124=2a_{22} = \frac{1}{2}|2 - 3(2)| = \frac{1}{2}|-4| = 2
  • a31=1233(1)=120=0a_{31} = \frac{1}{2}|3 - 3(1)| = \frac{1}{2}|0| = 0
  • a32=1233(2)=123=1.5a_{32} = \frac{1}{2}|3 - 3(2)| = \frac{1}{2}|-3| = 1.5
  1. Arrange elements into the matrix: A=[12.50.5201.5]A = \begin{bmatrix} 1 & 2.5 \\ 0.5 & 2 \\ 0 & 1.5 \end{bmatrix}

Explanation:

To construct a matrix based on a formula, identify the range of ii (rows) and jj (columns) from the given order, calculate the value for every possible (i,j)(i, j) pair, and place them in their respective grid positions.

Problem 2:

Find the values of x,y,x, y, and zz from the following equation: [x+y25+zxy]=[6258]\begin{bmatrix} x+y & 2 \\ 5+z & xy \end{bmatrix} = \begin{bmatrix} 6 & 2 \\ 5 & 8 \end{bmatrix}.

Solution:

  1. Since the matrices are equal, their corresponding elements must be equal.
  2. From a21=b21a_{21} = b_{21}: 5+z=5    z=05 + z = 5 \implies z = 0.
  3. From a11=b11a_{11} = b_{11}: x+y=6    y=6xx + y = 6 \implies y = 6 - x.
  4. From a22=b22a_{22} = b_{22}: xy=8xy = 8.
  5. Substitute y=6xy = 6 - x into xy=8xy = 8: x(6x)=8x(6 - x) = 8 6xx2=86x - x^2 = 8 x26x+8=0x^2 - 6x + 8 = 0 (x4)(x2)=0(x - 4)(x - 2) = 0 So, x=4x = 4 or x=2x = 2.
  6. If x=4x = 4, then y=64=2y = 6 - 4 = 2. If x=2x = 2, then y=62=4y = 6 - 2 = 4. Final values: (x=4,y=2,z=0)(x=4, y=2, z=0) or (x=2,y=4,z=0)(x=2, y=4, z=0).

Explanation:

This problem uses the principle of equality of matrices. By equating corresponding entries, we generate a system of algebraic equations that can be solved using substitution or factorization.