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Differential Equations - Definition, order and degree, general and particular solutions

Grade 12CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Definition of a Differential Equation: A differential equation is an equation that involves an independent variable, a dependent variable, and the derivatives of the dependent variable with respect to the independent variable. It acts as a mathematical rule describing how a quantity changes; for example, if we plot the solution on a graph, the differential equation defines the slope or curvature at every point (x,y)(x, y). Often written in the form y=f(x,y)y' = f(x, y) or F(x,y,y,y,,y(n))=0F(x, y, y', y'', \dots, y^{(n)}) = 0.

Order of a Differential Equation: The order is defined as the order of the highest order derivative appearing in the differential equation. For example, in the equation d2ydx2+3dydx+2y=0\frac{d^2y}{dx^2} + 3\frac{dy}{dx} + 2y = 0, the highest derivative is the second derivative, so the order is 22. Visually, the order indicates the level of 'complexity' in the rate of change—first order relates to velocity/slope, while second order relates to acceleration/curvature.

Degree of a Differential Equation: The degree is the power of the highest order derivative when the differential equation is expressed as a polynomial in its derivatives. Crucially, for the degree to be defined, the equation must be a polynomial in derivatives (i.e., derivatives should not be inside functions like sin\sin, cos\cos, or exe^x). For example, in (d2ydx2)3+(dydx)2=0\left(\frac{d^2y}{dx^2}\right)^3 + \left(\frac{dy}{dx}\right)^2 = 0, the degree is 33. If an equation is like dydx+sin(dydx)=0\frac{dy}{dx} + \sin\left(\frac{dy}{dx}\right) = 0, the degree is not defined.

General Solution: A solution of a differential equation that contains as many arbitrary constants as the order of the equation is called the general solution. Geometrically, a general solution represents a 'family of curves.' For example, y=x2+Cy = x^2 + C represents an infinite set of parabolas shifted vertically, where each value of CC corresponds to a different curve in the family.

Particular Solution: A solution obtained from the general solution by giving specific values to the arbitrary constants is called a particular solution. These values are typically determined using given initial conditions, such as y=y0y = y_0 when x=x0x = x_0. Visually, this corresponds to selecting one specific curve from the family of curves that passes through a particular point (x0,y0)(x_0, y_0) on the Cartesian plane.

Formation of Differential Equations: To form a differential equation representing a family of curves, we differentiate the equation of the family as many times as the number of arbitrary constants present and then eliminate those constants. If a family has nn arbitrary constants, the resulting differential equation will be of order nn.

Linearity of Differential Equations: A differential equation is linear if the dependent variable yy and its derivatives appear only in the first degree and are not multiplied together. Visually, linear equations are easier to solve and their solutions often follow the principle of superposition, where the sum of two solutions is also a solution.

📐Formulae

General form of an nthn^{th} order differential equation: F(x,y,dydx,d2ydx2,,dnydxn)=0F\left(x, y, \frac{dy}{dx}, \frac{d^2y}{dx^2}, \dots, \frac{d^ny}{dx^n}\right) = 0

First order derivative notation: y=dydxy' = \frac{dy}{dx}

Second order derivative notation: y=d2ydx2y'' = \frac{d^2y}{dx^2}

Relationship between constants and order: Number of arbitrary constants in General Solution=Order of the Differential Equation\text{Number of arbitrary constants in General Solution} = \text{Order of the Differential Equation}

Condition for Particular Solution: Number of arbitrary constants in Particular Solution=0\text{Number of arbitrary constants in Particular Solution} = 0

💡Examples

Problem 1:

Find the order and degree (if defined) of the differential equation: x2(d2ydx2)3+y(dydx)4+y5=0x^2 \left(\frac{d^2y}{dx^2}\right)^3 + y \left(\frac{dy}{dx}\right)^4 + y^5 = 0.

Solution:

Step 1: Identify the highest order derivative present in the equation. The derivatives are d2ydx2\frac{d^2y}{dx^2} (second order) and dydx\frac{dy}{dx} (first order). Therefore, the highest order is 22. \ Step 2: Check if the equation is a polynomial in its derivatives. Since all derivatives are raised to positive integer powers and are not inside transcendental functions, the degree is defined. \ Step 3: Identify the power of the highest order derivative. The term with the highest order derivative is (d2ydx2)3\left(\frac{d^2y}{dx^2}\right)^3, and its power is 33. \ Final Answer: Order = 22, Degree = 33.

Explanation:

The order is determined by the highest derivative (fracd2ydx2\\frac{d^2y}{dx^2}), and the degree is the exponent of that specific derivative.

Problem 2:

Verify that y=e3xy = e^{-3x} is a solution of the differential equation d2ydx2+dydx6y=0\frac{d^2y}{dx^2} + \frac{dy}{dx} - 6y = 0.

Solution:

Step 1: Find the first derivative of y=e3xy = e^{-3x}. \ dydx=ddx(e3x)=3e3x\frac{dy}{dx} = \frac{d}{dx}(e^{-3x}) = -3e^{-3x}. \ Step 2: Find the second derivative. \ d2ydx2=ddx(3e3x)=9e3x\frac{d^2y}{dx^2} = \frac{d}{dx}(-3e^{-3x}) = 9e^{-3x}. \ Step 3: Substitute yy, dydx\frac{dy}{dx}, and d2ydx2\frac{d^2y}{dx^2} into the Left Hand Side (LHS) of the differential equation. \ LHS=9e3x+(3e3x)6(e3x)LHS = 9e^{-3x} + (-3e^{-3x}) - 6(e^{-3x}) \ LHS=9e3x3e3x6e3x=(936)e3x=0LHS = 9e^{-3x} - 3e^{-3x} - 6e^{-3x} = (9 - 3 - 6)e^{-3x} = 0. \ Step 4: Compare LHS with RHS. \ LHS=0=RHSLHS = 0 = RHS. \ Since LHS = RHS, the given function is a solution.

Explanation:

Verification involves calculating the required derivatives and substituting them back into the original equation to see if it satisfies the identity.