Review the key concepts, formulae, and examples before starting your quiz.
πConcepts
A function from a set to a set is a special relation where every element is associated with exactly one element . Visually, this means in an arrow diagram, every element in the domain has exactly one outgoing arrow. In a coordinate plane, this satisfies the Vertical Line Test: no vertical line intersects the graph of a function at more than one point.
The Domain of a function is the set of all possible input values () for which the function is defined. For real-valued functions, we must ensure that denominators are non-zero (to avoid division by zero) and expressions under even roots (like ) are non-negative. On a graph, the domain is the horizontal span of the curve along the -axis.
The Range is the set of all actual output values ( or ) that the function produces. The Codomain is the set that contains the range. Visually, the range is represented by the vertical span of the graph along the -axis.
The Identity Function is defined by . Its graph is a straight line passing through the origin at a angle to the -axis, covering all real numbers for both domain and range. The Constant Function results in a horizontal line parallel to the -axis, where the range is the singleton set .
The Modulus Function returns the absolute value of . The graph forms a symmetric 'V' shape with the vertex at the origin . Its domain is and its range is . It is defined piecewise as if and if .
The Signum Function for and provides the sign of the input. Its graph consists of two horizontal rays: for and for , along with an isolated point at . The range is specifically the set .
The Greatest Integer Function (also known as the floor function) outputs the greatest integer less than or equal to . The graph resembles a series of 'steps' or a 'staircase,' where each step is closed on the left end and open on the right end (e.g., the interval stays at ).
Algebra of Functions: For two functions and , we can define , , and . The domain of these new functions is the intersection of the domains of and , denoted as .
πFormulae
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π‘Examples
Problem 1:
Find the domain and range of the function .
Solution:
- For the function to be defined, the expression inside the square root must be non-negative: .
- Solve the inequality: , which gives . Thus, Domain .
- To find the range, let . Since it is a square root, .
- Squaring both sides: .
- Since , we have , so .
- Combining and , the Range is .
Explanation:
The domain is restricted by the square root condition (radicand ). The range is restricted by both the output of the square root (always non-negative) and the maximum value of the radicand.
Problem 2:
Find the domain of .
Solution:
- The function is a rational function, so it is defined for all except where the denominator equals zero.
- Set the denominator to zero: .
- Factor the quadratic: .
- Find the roots: and .
- Therefore, the domain is the set of all real numbers except and .
- In interval notation: Domain or .
Explanation:
For rational functions, the numerator can be anything, but the denominator cannot be zero as division by zero is undefined in real numbers.