krit.club logo

Mathematical Reasoning - Statements and Logical Connectives

Grade 11ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A Mathematical Statement is a declarative sentence which is either definitely true or definitely false, but not both. For example, 'The square of 4 is 16' is a statement, while 'Give me that book' is a command and not a mathematical statement. Visually, imagine a binary switch that can only be in the 'ON' (True) or 'OFF' (False) position, never in between.

Negation of a statement pp is denoted by p\sim p. If pp is true, p\sim p is false; if pp is false, p\sim p is true. This can be visualized as a simple two-column Truth Table where the input column pp lists values T,FT, F and the output column p\sim p flips them to F,TF, T.

Compound Statements are formed by combining two or more simple statements using logical connectives like 'and' (wedge\\wedge), 'or' (vee\\vee), 'if...then' (Rightarrow\\Rightarrow), and 'if and only if' (Leftrightarrow\\Leftrightarrow). Visually, this creates a branching structure or a Truth Table with 2n2^n rows, where nn is the number of simple statements.

Conjunction (pwedgeqp \\wedge q) is true only when both component statements pp and qq are true. In a Venn Diagram representation, this corresponds to the intersection of two sets, where the shaded area represents only the region shared by both pp and qq.

Disjunction (pveeqp \\vee q) is false only when both component statements pp and qq are false. In all other cases, it is true. Visually, in a Venn Diagram, this is the union of two sets, covering all regions belonging to pp, qq, or both.

A Conditional Statement pRightarrowqp \\Rightarrow q (read as 'If pp, then qq') is false only in one specific case: when the antecedent pp is true and the consequent qq is false (TRightarrowFT \\Rightarrow F). Visually, think of a contract: the contract is broken (False) only if the first party fulfills their duty (pp is TT) but the second party does not deliver (qq is FF).

Biconditional Statement pLeftrightarrowqp \\Leftrightarrow q (read as 'pp if and only if qq') is true when both pp and qq have the same truth value (both True or both False). In a Truth Table, the resulting column shows 'True' for the (T,T)(T, T) and (F,F)(F, F) rows and 'False' otherwise.

Tautology and Contradiction: A compound statement that is always true regardless of the truth values of its components is a Tautology. Conversely, a statement that is always false is a Contradiction. Visually, a Tautology is a Truth Table column filled entirely with 'T', while a Contradiction is a column filled entirely with 'F'.

📐Formulae

Negation of Conjunction (De Morgan's Law): (pwedgeq)equivsimpveesimq\sim(p \\wedge q) \\equiv \\sim p \\vee \\sim q

Negation of Disjunction (De Morgan's Law): (pveeq)equivsimpwedgesimq\sim(p \\vee q) \\equiv \\sim p \\wedge \\sim q

Conditional as Disjunction: pRightarrowqequivsimpveeqp \\Rightarrow q \\equiv \\sim p \\vee q

Negation of Conditional: (pRightarrowq)equivpwedgesimq\sim(p \\Rightarrow q) \\equiv p \\wedge \\sim q

Contrapositive: The contrapositive of pRightarrowqp \\Rightarrow q is qRightarrowsimp\sim q \\Rightarrow \\sim p (Logically Equivalent)

Converse: The converse of pRightarrowqp \\Rightarrow q is qRightarrowpq \\Rightarrow p

Inverse: The inverse of pRightarrowqp \\Rightarrow q is pRightarrowsimq\sim p \\Rightarrow \\sim q

Biconditional Identity: pLeftrightarrowqequiv(pRightarrowq)wedge(qRightarrowp)p \\Leftrightarrow q \\equiv (p \\Rightarrow q) \\wedge (q \\Rightarrow p)

💡Examples

Problem 1:

Construct a truth table for the statement (pwedgeq)Rightarrowp(p \\wedge q) \\Rightarrow p and determine if it is a tautology.

Solution:

  1. List all combinations of pp and qq: \n Row 1: p=T,q=Tp=T, q=T \n Row 2: p=T,q=Fp=T, q=F \n Row 3: p=F,q=Tp=F, q=T \n Row 4: p=F,q=Fp=F, q=F \n 2. Evaluate (pwedgeq)(p \\wedge q): \n Row 1: TwedgeT=TT \\wedge T = T \n Row 2: TwedgeF=FT \\wedge F = F \n Row 3: FwedgeT=FF \\wedge T = F \n Row 4: FwedgeF=FF \\wedge F = F \n 3. Evaluate (pwedgeq)Rightarrowp(p \\wedge q) \\Rightarrow p: \n Row 1: TRightarrowT=TT \\Rightarrow T = T \n Row 2: FRightarrowT=TF \\Rightarrow T = T \n Row 3: FRightarrowF=TF \\Rightarrow F = T \n Row 4: FRightarrowF=TF \\Rightarrow F = T

Explanation:

Since the final column of the truth table consists only of 'T' (True) values for all possible combinations of pp and qq, the statement (pwedgeq)Rightarrowp(p \\wedge q) \\Rightarrow p is a Tautology.

Problem 2:

Write the negation of the statement: 'If it rains, then the match will be cancelled.'

Solution:

  1. Identify component statements: \n pp: It rains. \n qq: The match will be cancelled. \n 2. Represent the original statement: pRightarrowqp \\Rightarrow q. \n 3. Use the negation formula: sim(pRightarrowq)equivpwedgesimq\\sim(p \\Rightarrow q) \\equiv p \\wedge \\sim q. \n 4. Translate back to English: 'It rains and the match will not be cancelled.'

Explanation:

To negate a conditional statement 'If p then q', we state that 'p' occurs but 'q' does not. This follows the logical equivalence sim(pRightarrowq)equivpwedgesimq\\sim(p \\Rightarrow q) \\equiv p \\wedge \\sim q.