Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Coordinate Axes and Origin: In 3D geometry, we use three mutually perpendicular lines called the , , and axes that intersect at a single point called the Origin . Visually, these axes can be imagined as the lines formed where two walls and the floor of a room meet.
Coordinate Planes: The three axes taken in pairs determine three coordinate planes: the -plane (where ), the -plane (where ), and the -plane (where ). These planes are like the flat surfaces of the walls and floor in a 3D space.
Octants: The three coordinate planes divide the entire space into eight regions known as octants. The signs of the coordinates of a point vary depending on its octant; for instance, in the first octant, all coordinates are positive , while in the eighth octant, they are .
Coordinates of a Point: A point in space is represented by an ordered triple . The value of is the signed perpendicular distance from the -plane, from the -plane, and from the -plane. Visually, moving from the origin to involves traveling along the -axis, then parallel to the -axis, and finally parallel to the -axis.
Distance from Axes: The perpendicular distance of a point from the -axis is given by , from the -axis by , and from the -axis by .
Section Formula Concept: This describes the position of a point that divides a line segment joining two points and . If the point is between and , it is internal division; if it lies on the extension of the line segment, it is external division.
Centroid of a Triangle: The centroid is the point where the medians of a triangle meet in 3D space. It is found by taking the arithmetic mean of the , , and coordinates of the three vertices.
📐Formulae
Distance between two points and :
Distance from Origin to point :
Internal Section Formula:
External Section Formula:
Midpoint Formula:
Centroid of a Triangle:
💡Examples
Problem 1:
Find the distance between the points and .
Solution:
- Identify the coordinates: and . \n2. Apply the distance formula: . \n3. Substitute the values: . \n4. Simplify: . \n5. . \n6. Final value: units.
Explanation:
The distance formula calculates the straight-line spatial distance between two points by finding the square root of the sum of the squares of the differences between their respective coordinates.
Problem 2:
Find the coordinates of the point which divides the line segment joining and in the ratio internally.
Solution:
- Coordinates: , and ratio . \n2. Use Internal Section Formula: , , . \n3. For : . \n4. For : . \n5. For : . \n6. The point is .
Explanation:
The section formula determines the coordinates of a point that partitions a line segment according to a specific ratio. Since it is internal division, we add the products in the numerator and the terms in the denominator.