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Geometry and Trigonometry - Graphs of Trigonometric Functions

Grade 11IB

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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General Sine and Cosine Transformations: The functions y=asin⁑(b(xβˆ’c))+dy = a \sin(b(x - c)) + d and y=acos⁑(b(xβˆ’c))+dy = a \cos(b(x - c)) + d represent the standard wave models. Visually, these functions create a smooth, repeating 'wave' shape. The cosine graph starts at its maximum value when the phase shift is zero, while the sine graph starts at the midline and moves upwards.

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Amplitude (∣a∣|a|): The amplitude is the vertical stretch of the graph, representing half the distance between the maximum and minimum points. Visually, it is the height of the wave crest above the horizontal midline y=dy = d. If a<0a < 0, the graph is reflected across the midline.

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Period and Horizontal Scale (bb): The period is the horizontal length of one complete cycle. It is calculated as 2Ο€b\frac{2\pi}{b} for radians or 360∘b\frac{360^{\circ}}{b} for degrees. Visually, a larger bb value 'compresses' the graph horizontally, meaning more cycles appear within the same distance.

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Phase Shift (cc): The phase shift is the horizontal translation of the graph. A positive cc moves the graph to the right, and a negative cc moves it to the left. For a sine wave y=sin⁑(xβˆ’c)y = \sin(x - c), the point that usually starts at (0,0)(0,0) is shifted to (c,0)(c,0).

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Vertical Shift and Midline (dd): The constant dd shifts the entire graph up or down. Visually, this creates a new horizontal 'principal axis' or midline at y=dy = d, around which the wave oscillates. The maximum value is d+∣a∣d + |a| and the minimum value is dβˆ’βˆ£a∣d - |a|.

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The Tangent Function y=atan⁑(b(xβˆ’c))+dy = a \tan(b(x - c)) + d: Unlike sine and cosine, the tangent graph is not a continuous wave but a series of separate branches. It has a period of Ο€b\frac{\pi}{b} (or 180∘b\frac{180^{\circ}}{b}) and features vertical asymptotes where the function is undefined (e.g., at x=Ο€2x = \frac{\pi}{2} for y=tan⁑(x)y = \tan(x)). Visually, it always increases between asymptotes and passes through the midline at the center of each period.

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Domain and Range: For sine and cosine functions, the domain is all real numbers x∈Rx \in \mathbb{R}, and the range is restricted to [dβˆ’βˆ£a∣,d+∣a∣][d - |a|, d + |a|]. For the tangent function, the range is all real numbers y∈Ry \in \mathbb{R}, but the domain excludes values where the vertical asymptotes occur.

πŸ“Formulae

Amplitude=∣a∣=Maxβˆ’Min2Amplitude = |a| = \frac{Max - Min}{2}

Midline(VerticalShift) d=Max+Min2Midline (Vertical Shift) \, d = \frac{Max + Min}{2}

Period=2Ο€bΒ (radians)Β orΒ 360∘bΒ (degrees)Period = \frac{2\pi}{b} \text{ (radians) or } \frac{360^{\circ}}{b} \text{ (degrees)}

b=2Ο€Periodb = \frac{2\pi}{Period}

Range:[dβˆ’βˆ£a∣,d+∣a∣]Range: [d - |a|, d + |a|]

VerticalΒ AsymptotesΒ ofΒ tan⁑(x):x=Ο€2+kΟ€, k∈Z\text{Vertical Asymptotes of } \tan(x): x = \frac{\pi}{2} + k\pi, \, k \in \mathbb{Z}

πŸ’‘Examples

Problem 1:

Determine the amplitude, period, and range of the function f(x)=3sin⁑(2xβˆ’Ο€2)+5f(x) = 3 \sin(2x - \frac{\pi}{2}) + 5.

Solution:

  1. Identify parameters: a=3a = 3, b=2b = 2, c=Ο€4c = \frac{\pi}{4} (since 2xβˆ’Ο€2=2(xβˆ’Ο€4)2x - \frac{\pi}{2} = 2(x - \frac{\pi}{4})), and d=5d = 5.
  2. Amplitude: ∣a∣=∣3∣=3|a| = |3| = 3.
  3. Period: P=2Ο€b=2Ο€2=Ο€P = \frac{2\pi}{b} = \frac{2\pi}{2} = \pi.
  4. Range: The midline is y=5y = 5. The minimum is 5βˆ’3=25 - 3 = 2 and the maximum is 5+3=85 + 3 = 8. Thus, the range is [2,8][2, 8].

Explanation:

We extract the transformation constants from the general form y=asin⁑(b(xβˆ’c))+dy = a \sin(b(x-c)) + d. Note that bb must be factored out to find the true phase shift cc.

Problem 2:

A trigonometric function has a maximum point at (3,12)(3, 12) and the next minimum point at (7,4)(7, 4). Find an equation for the function in the form y=acos⁑(b(xβˆ’c))+dy = a \cos(b(x-c)) + d.

Solution:

  1. Find amplitude aa: a=12βˆ’42=4a = \frac{12 - 4}{2} = 4.
  2. Find vertical shift dd: d=12+42=8d = \frac{12 + 4}{2} = 8.
  3. Find the period: The horizontal distance from a max to a min is half a period. 7βˆ’3=47 - 3 = 4, so Period=4Γ—2=8Period = 4 \times 2 = 8.
  4. Calculate bb: b=2Ο€8=Ο€4b = \frac{2\pi}{8} = \frac{\pi}{4}.
  5. Find phase shift cc: A cosine graph normally starts at a maximum at x=0x=0. Since our maximum is at x=3x=3, c=3c = 3.
  6. Final equation: y=4cos⁑(Ο€4(xβˆ’3))+8y = 4 \cos(\frac{\pi}{4}(x - 3)) + 8.

Explanation:

We use the coordinates of the turning points to calculate the vertical and horizontal stretches and shifts. For cosine, the phase shift cc corresponds directly to the x-coordinate of a maximum point.