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Functions - Graphing Functions and their Characteristics

Grade 11IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Domain and Range: The domain is the set of all possible input values (xx-values) for which the function is defined, visually represented as the horizontal 'spread' of the graph. The range is the set of all output values (yy-values), represented as the vertical 'spread'. For example, the graph of f(x)=xf(x) = \sqrt{x} starts at (0,0)(0,0) and extends infinitely to the right and upwards, meaning domain x0x \geq 0 and range y0y \geq 0.

Vertical Line Test: A visual method used to determine if a relation is a function. If any vertical line drawn through the graph intersects the curve at more than one point, the relation is not a function because one input xx maps to multiple outputs yy.

Intercepts: The yy-intercept is the point where the graph crosses the vertical axis (calculated by setting x=0x = 0). The xx-intercepts, also known as roots or zeros, are the points where the graph crosses the horizontal axis (calculated by setting f(x)=0f(x) = 0). Visually, these are the 'anchor points' of the sketch.

Asymptotes: These are lines that the graph approaches but never actually reaches. Vertical asymptotes often occur where the denominator of a rational function is zero, creating a 'break' in the graph. Horizontal asymptotes describe the end behavior of the function as xx approaches \infty or -\infty, appearing as a flat boundary line.

Function Transformations: Shifts and stretches change the position and shape of the parent graph. Adding kk to the function (f(x)+kf(x) + k) shifts the graph vertically, while subtracting hh from the input (f(xh)f(x - h)) shifts it horizontally. A negative sign outside the function (f(x)-f(x)) reflects the graph across the xx-axis, flipping it upside down.

Quadratic Characteristics: The graph of a quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c is a parabola. It features a vertex, which is the maximum or minimum point where the graph turns. An imaginary vertical line called the axis of symmetry passes through the vertex, dividing the parabola into two identical mirror images.

Inverse Functions and Symmetry: The graph of an inverse function f1(x)f^{-1}(x) is a reflection of the original function f(x)f(x) across the diagonal line y=xy = x. If a point (a,b)(a, b) lies on the original graph, the point (b,a)(b, a) will lie on the graph of the inverse.

Increasing and Decreasing Intervals: A function is increasing on an interval if, as you move from left to right, the yy-values go up (the slope is positive). It is decreasing if the yy-values go down (the slope is negative). Local maximums and minimums occur where the function switches between these states.

📐Formulae

f(x)=a(xh)2+kf(x) = a(x - h)^2 + k (Quadratic Vertex Form)

x=b2ax = -\frac{b}{2a} (Axis of Symmetry / x-coordinate of Vertex)

Δ=b24ac\Delta = b^2 - 4ac (Discriminant for determining number of x-intercepts)

g(x)=af(b(xh))+kg(x) = a \cdot f(b(x - h)) + k (General Transformation Formula)

(fg)(x)=f(g(x))(f \circ g)(x) = f(g(x)) (Composite Function)

f(f1(x))=xf(f^{-1}(x)) = x (Inverse Function Identity)

💡Examples

Problem 1:

Given the quadratic function f(x)=x26x+5f(x) = x^2 - 6x + 5, find the yy-intercept, xx-intercepts, and the coordinates of the vertex.

Solution:

  1. yy-intercept: Set x=0x = 0. f(0)=026(0)+5=5f(0) = 0^2 - 6(0) + 5 = 5. The yy-intercept is (0,5)(0, 5).
  2. xx-intercepts: Set f(x)=0f(x) = 0. Solve x26x+5=0x^2 - 6x + 5 = 0. Factoring gives (x5)(x1)=0(x - 5)(x - 1) = 0. Thus, x=5x = 5 and x=1x = 1. The xx-intercepts are (1,0)(1, 0) and (5,0)(5, 0).
  3. Vertex: The xx-coordinate is h=b2a=62(1)=3h = -\frac{b}{2a} = -\frac{-6}{2(1)} = 3. The yy-coordinate is k=f(3)=326(3)+5=918+5=4k = f(3) = 3^2 - 6(3) + 5 = 9 - 18 + 5 = -4. The vertex is (3,4)(3, -4).

Explanation:

We use algebraic substitution for intercepts and the vertex formula for the turning point. The vertex (3,4)(3, -4) represents the minimum point because the coefficient of x2x^2 is positive.

Problem 2:

Describe the transformations required to obtain the graph of g(x)=2(x+3)2+4g(x) = -2(x + 3)^2 + 4 from the parent function f(x)=x2f(x) = x^2.

Solution:

  1. Horizontal Shift: The (x+3)(x + 3) indicates a translation of 33 units to the left.
  2. Vertical Stretch: The factor of 22 indicates a vertical stretch by a scale factor of 22.
  3. Reflection: The negative sign in front of the 22 indicates a reflection across the xx-axis.
  4. Vertical Shift: The +4+ 4 indicates a translation of 44 units upwards.

Explanation:

Transformations are applied in the order of operations (BIDMAS/PEMDAS). Horizontal shifts occur within the brackets, while vertical stretches, reflections, and vertical shifts are applied to the output.