Review the key concepts, formulae, and examples before starting your quiz.
πConcepts
The Average Rate of Change is defined as the gradient of a secant line that passes through two points on a curve, and . Visually, this is the slope of a straight line connecting two distinct locations on a graph, representing how much the function changes over the interval .
The Instantaneous Rate of Change is the gradient of the curve at one specific point. Visually, this is the slope of the tangent lineβa line that just touches the curve at that point. Differentiation is the mathematical tool used to calculate this exact slope.
Differentiation from First Principles is the formal algebraic process of finding the derivative by taking the limit of the secant gradient. As the horizontal distance between two points on a graph shrinks toward zero, the secant line rotates and eventually coincides with the tangent line at the point .
The concept of the Limit () is central to calculus. In a visual sense, it describes the behavior of the gradient as the 'run' of our slope calculation becomes infinitely small. We cannot simply divide by zero, so we use the limit to observe the value the gradient approaches as vanishes.
Derivative Notation: The derivative of a function is commonly written as or . Geometrically, if you were to plot , the -value of this new graph at any point would represent the steepness (slope) of the original function at that same coordinate.
Tangents and Normals: The tangent is a line with the gradient . The normal is a line perpendicular to the tangent at the point of contact. Visually, the normal line stands at a angle to the curve; its gradient is the negative reciprocal of the tangent's gradient, calculated as .
πFormulae
Gradient of a secant:
The Derivative from First Principles:
Leibniz Notation:
Equation of a Tangent Line:
Gradient of a Normal Line:
π‘Examples
Problem 1:
Use differentiation from first principles to find the derivative of .
Solution:
Step 1: Substitute the function into the first principles formula: Step 2: Expand the term: Step 3: Simplify the numerator by cancelling terms ( and ): Step 4: Factor out from the numerator and divide: Step 5: Apply the limit by letting :
Explanation:
This approach shows that for every point on the parabola , the slope of the tangent line is exactly twice the -coordinate.
Problem 2:
Find the gradient of the tangent to the curve at the point where using first principles.
Solution:
Step 1: Set up the limit for : Step 2: Expand and simplify: Step 3: Divide by : Step 4: Evaluate the limit: Step 5: Substitute to find the specific gradient:
Explanation:
The general derivative gives the slope at any point. By substituting , we find that the line touching the curve at that specific point has a very steep positive gradient of .