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Straight Lines - Various Forms of the Equation of a Line: Horizontal/Vertical, Point-Slope, Two-Point, Slope-Intercept, Intercept Form

Grade 11CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Horizontal and Vertical Lines: A horizontal line is parallel to the x-axis and has a constant y-coordinate for every point; it appears as a flat line crossing the y-axis at (0,k)(0, k). A vertical line is parallel to the y-axis with a constant x-coordinate, appearing as a straight upright line crossing the x-axis at (h,0)(h, 0).

Slope-Intercept Form: This form is used when the slope mm and the y-intercept cc are known. Visually, cc is the point where the line crosses the vertical axis (0,c)(0, c), and mm dictates the 'steepness' or 'gradient' of the line as it moves across the coordinate plane.

Point-Slope Form: This equation is used when we know one specific point (x1,y1)(x_1, y_1) on the line and its slope mm. It is based on the principle that the slope between any arbitrary point (x,y)(x, y) and the fixed point (x1,y1)(x_1, y_1) must be constant.

Two-Point Form: This is used when the coordinates of two distinct points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are given. Geometrically, this defines a unique straight line passing through both points, where the slope is first calculated as the vertical change divided by the horizontal change.

Intercept Form: This form relates the line to its intercepts on both the x-axis (at aa) and the y-axis (at bb). Visually, the line cuts the x-axis at (a,0)(a, 0) and the y-axis at (0,b)(0, b), creating a triangle with the origin.

Geometric Significance of Slope (mm): The slope represents tanθ\tan \theta, where θ\theta is the angle of inclination with the positive direction of the x-axis. If m>0m > 0, the line rises from left to right; if m<0m < 0, it falls from left to right.

📐Formulae

Horizontal Line: y=ky = k

Vertical Line: x=hx = h

Slope-Intercept Form: y=mx+cy = mx + c

Point-Slope Form: yy1=m(xx1)y - y_1 = m(x - x_1)

Two-Point Form: yy1=y2y1x2x1(xx1)y - y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x - x_1)

InterceptForm:xa+yb=1Intercept Form: \frac{x}{a} + \frac{y}{b} = 1

Slope (mm) from two points: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

Slope (mm) from inclination: m=tanθm = \tan \theta

💡Examples

Problem 1:

Find the equation of the line passing through the point (2,3)(2, -3) with a slope of 44.

Solution:

  1. Identify the given values: (x1,y1)=(2,3)(x_1, y_1) = (2, -3) and m=4m = 4.
  2. Use the Point-Slope form: yy1=m(xx1)y - y_1 = m(x - x_1).
  3. Substitute the values: y(3)=4(x2)y - (-3) = 4(x - 2).
  4. Simplify: y+3=4x8y + 3 = 4x - 8.
  5. Rearrange into general form: 4xy11=04x - y - 11 = 0.

Explanation:

We use the point-slope form because we are given one specific point and the gradient of the line.

Problem 2:

Find the equation of the line that cuts off intercepts 33 and 2-2 on the x and y axes respectively.

Solution:

  1. Identify the intercepts: a=3a = 3 (x-intercept) and b=2b = -2 (y-intercept).
  2. Use the Intercept form: xa+yb=1\frac{x}{a} + \frac{y}{b} = 1.
  3. Substitute the values: x3+y2=1\frac{x}{3} + \frac{y}{-2} = 1.
  4. Find the common denominator to simplify: 2x3y6=1\frac{2x - 3y}{6} = 1.
  5. Final equation: 2x3y=62x - 3y = 6 or 2x3y6=02x - 3y - 6 = 0.

Explanation:

The intercept form is the most direct method here as it utilizes the points (3,0)(3, 0) and (0,2)(0, -2) where the line crosses the axes.