Straight Lines - Various Forms of the Equation of a Line: Horizontal/Vertical, Point-Slope, Two-Point, Slope-Intercept, Intercept Form
Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Horizontal and Vertical Lines: A horizontal line is parallel to the x-axis and has a constant y-coordinate for every point; it appears as a flat line crossing the y-axis at . A vertical line is parallel to the y-axis with a constant x-coordinate, appearing as a straight upright line crossing the x-axis at .
Slope-Intercept Form: This form is used when the slope and the y-intercept are known. Visually, is the point where the line crosses the vertical axis , and dictates the 'steepness' or 'gradient' of the line as it moves across the coordinate plane.
Point-Slope Form: This equation is used when we know one specific point on the line and its slope . It is based on the principle that the slope between any arbitrary point and the fixed point must be constant.
Two-Point Form: This is used when the coordinates of two distinct points and are given. Geometrically, this defines a unique straight line passing through both points, where the slope is first calculated as the vertical change divided by the horizontal change.
Intercept Form: This form relates the line to its intercepts on both the x-axis (at ) and the y-axis (at ). Visually, the line cuts the x-axis at and the y-axis at , creating a triangle with the origin.
Geometric Significance of Slope (): The slope represents , where is the angle of inclination with the positive direction of the x-axis. If , the line rises from left to right; if , it falls from left to right.
📐Formulae
Horizontal Line:
Vertical Line:
Slope-Intercept Form:
Point-Slope Form:
Two-Point Form:
Slope () from two points:
Slope () from inclination:
💡Examples
Problem 1:
Find the equation of the line passing through the point with a slope of .
Solution:
- Identify the given values: and .
- Use the Point-Slope form: .
- Substitute the values: .
- Simplify: .
- Rearrange into general form: .
Explanation:
We use the point-slope form because we are given one specific point and the gradient of the line.
Problem 2:
Find the equation of the line that cuts off intercepts and on the x and y axes respectively.
Solution:
- Identify the intercepts: (x-intercept) and (y-intercept).
- Use the Intercept form: .
- Substitute the values: .
- Find the common denominator to simplify: .
- Final equation: or .
Explanation:
The intercept form is the most direct method here as it utilizes the points and where the line crosses the axes.