Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Definition of Arithmetic Mean (A.M.): For any two positive real numbers and , the Arithmetic Mean is the value . Visually, on a number line, represents the exact midpoint between the points and .
Definition of Geometric Mean (G.M.): For any two positive real numbers and , the Geometric Mean is the value . Geometrically, if you have a rectangle with sides and , is the side of a square that has the same area as that rectangle.
The A.M.-G.M. Inequality: For any two positive real numbers and , the Arithmetic Mean is always greater than or equal to the Geometric Mean (). On a coordinate plane, the value of will always be located at or to the right of on the horizontal axis.
Condition for Equality: The relationship occurs if and only if the two numbers are equal, i.e., . If , then is strictly greater than ().
Geometric Visualization via Semicircle: Consider a semicircle with a diameter of length . The radius of this circle is the A.M., which is . If a perpendicular line is drawn from the point where segments and meet on the diameter to the circumference, the length of this perpendicular is the G.M., . Since the radius is the maximum possible height within the semicircle, it visually demonstrates that A.M. G.M.
Quadratic Equation Connection: If and are the A.M. and G.M. of two numbers and , then these numbers are the roots of the quadratic equation . This relates the means to the algebraic structure of polynomial roots.
Nature of Roots: Since , the discriminant of the equation , which is , is always non-negative. This ensures that the numbers and are always real when and are given such that .
📐Formulae
Roots:
💡Examples
Problem 1:
If the Arithmetic Mean (A.M.) of two positive numbers is and their Geometric Mean (G.M.) is , find the numbers.
Solution:
Step 1: Let the two numbers be and . We are given and . Step 2: Use the quadratic equation formula for numbers when A.M. and G.M. are known: . Step 3: Substitute the values: . Step 4: Solve the quadratic equation by factoring: . Step 5: The roots are and . Therefore, the two numbers are and .
Explanation:
This approach uses the property that two numbers are the roots of a quadratic equation formed using their A.M. and G.M. Alternatively, one could solve the system and .
Problem 2:
Prove that for any two positive real numbers and , the Arithmetic Mean is always greater than or equal to the Geometric Mean.
Solution:
Step 1: Consider the difference . Step 2: Take a common denominator: . Step 3: Observe that the numerator is a perfect square: . Step 4: Thus, . Step 5: Since the square of any real number is non-negative, . Therefore, , which implies .
Explanation:
This algebraic proof demonstrates that the difference between A.M. and G.M. is proportional to the square of the difference of the square roots of the numbers, which can never be negative.