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Relations and Functions - Cartesian Product of Sets

Grade 11CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Ordered Pairs: An ordered pair consists of two objects or elements in a fixed order, typically written as (a,b)(a, b). In this pair, aa is called the first element and bb is the second element. Visually, this can be represented as a specific point on a 2D Cartesian plane, where switching the order to (b,a)(b, a) would result in a different point unless a=ba = b.

Equality of Ordered Pairs: Two ordered pairs (a1,b1)(a_1, b_1) and (a2,b2)(a_2, b_2) are equal if and only if their corresponding first elements are equal and their corresponding second elements are equal, i.e., a1=a2a_1 = a_2 and b1=b2b_1 = b_2.

Cartesian Product of Two Sets: For two non-empty sets AA and BB, the Cartesian product AtimesBA \\times B is the set of all ordered pairs (a,b)(a, b) such that ainAa \\in A and binBb \\in B. Conceptually, if you list elements of AA along a horizontal axis and elements of BB along a vertical axis, the Cartesian product represents every intersection point in the resulting grid.

Cardinality of Cartesian Product: If set AA has pp elements and set BB has qq elements, then the number of elements in the Cartesian product AtimesBA \\times B is the product of the number of elements in each set. This is expressed as n(AtimesB)=n(A)timesn(B)n(A \\times B) = n(A) \\times n(B).

Cartesian Product with Empty Set: If either set AA or set BB is an empty set (null set phi\\phi), then the Cartesian product AtimesBA \\times B is also an empty set, because no ordered pairs can be formed. Symbolically, Atimesphi=phiA \\times \\phi = \\phi.

Cartesian Product of Three Sets: The product AtimesBtimesCA \\times B \\times C results in a set of ordered triplets (a,b,c)(a, b, c) where ainA,binB,a \\in A, b \\in B, and cinCc \\in C. Visually, this extends the 2D grid concept into 3D space, where each triplet represents a unique point (x,y,z)(x, y, z) in a three-dimensional coordinate system.

Graphical Representation (Arrow Diagrams): A Cartesian product can be visualized using an arrow diagram where two closed loops represent sets AA and BB. Every element in the first loop has an arrow pointing to every single element in the second loop, representing all possible pairings.

📐Formulae

AtimesB=(a,b):ainA,binBA \\times B = \\{ (a, b) : a \\in A, b \\in B \\}

(a,b)=(x,y)impliesa=xtextandb=y(a, b) = (x, y) \\implies a = x \\text{ and } b = y

n(AtimesB)=n(A)timesn(B)n(A \\times B) = n(A) \\times n(B)

Atimesphi=phiA \\times \\phi = \\phi

Atimes(BcupC)=(AtimesB)cup(AtimesC)A \\times (B \\cup C) = (A \\times B) \\cup (A \\times C)

Atimes(BcapC)=(AtimesB)cap(AtimesC)A \\times (B \\cap C) = (A \\times B) \\cap (A \\times C)

AtimesAtimesA=(a,b,c):a,b,cinAA \\times A \\times A = \\{ (a, b, c) : a, b, c \\in A \\}

💡Examples

Problem 1:

If the ordered pairs (x+1,y2)(x + 1, y - 2) and (3,1)(3, 1) are equal, find the values of xx and yy.

Solution:

Step 1: Use the definition of equality of ordered pairs, which states that corresponding elements must be equal. Step 2: Set the first elements equal: x+1=3x + 1 = 3. Step 3: Solve for xx: x=31impliesx=2x = 3 - 1 \\implies x = 2. Step 4: Set the second elements equal: y2=1y - 2 = 1. Step 5: Solve for yy: y=1+2impliesy=3y = 1 + 2 \\implies y = 3. Final Answer: x=2,y=3x = 2, y = 3.

Explanation:

Since (a,b)=(c,d)(a, b) = (c, d) implies a=ca=c and b=db=d, we create two simple linear equations to solve for the unknown variables.

Problem 2:

Let A=1,2A = \\{1, 2\\} and B=3,4B = \\{3, 4\\}. Write AtimesBA \\times B and find n(AtimesB)n(A \\times B).

Solution:

Step 1: Identify elements of AA and BB. A=1,2A = \\{1, 2\\}, B=3,4B = \\{3, 4\\}. Step 2: Form all possible ordered pairs where the first element is from AA and the second is from BB. Pairs with 11 as first element: (1,3),(1,4)(1, 3), (1, 4). Pairs with 22 as first element: (2,3),(2,4)(2, 3), (2, 4). Step 3: Combine them into a set: AtimesB=(1,3),(1,4),(2,3),(2,4).A \\times B = \\{(1, 3), (1, 4), (2, 3), (2, 4)\\}. Step 4: Calculate n(AtimesB)n(A \\times B). Since n(A)=2n(A) = 2 and n(B)=2n(B) = 2, n(AtimesB)=2times2=4n(A \\times B) = 2 \\times 2 = 4.

Explanation:

The Cartesian product is found by pairing every element of the first set with every element of the second set systematically. The total count follows the fundamental principle of counting.