Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Direct Method of Validation: This method is used to prove a conditional statement of the form . We assume that the antecedent is true and use logical reasoning, axioms, and previously proven theorems to show that the consequent must also be true. Visually, imagine a directed path starting at point and moving forward step-by-step through valid logical gates until reaching destination .
Method of Contrapositive: This method relies on the logical equivalence between a statement and its contrapositive: . To prove the statement, we assume that is false (i.e., is true) and demonstrate that must therefore be false (i.e., is true). This can be visualized as looking at the logical flow in a mirror; if the reflection (negation) of the result leads back to the reflection of the start, the original path is valid.
Method of Contradiction (Reductio ad Absurdum): To prove a statement is true, we begin by assuming the negation is true. We then follow a chain of logical deductions until we reach a contradiction (a statement that is clearly false or conflicts with our initial assumption). This implies that our assumption was wrong, hence must be true. Visually, this is like exploring a branch in a decision tree that leads to a 'Dead End' or a logical 'Wall,' forcing us back to the only other possible branch.
Validation by Counter-example: This method is used to disprove a statement that is claimed to be true for all cases (e.g., 'For all '). To invalidate such a statement, we only need to find a single instance where the condition does not hold. Visually, if a property is claimed to cover an entire shaded region, a counter-example is a single 'outlier' point located outside that shaded boundary.
Validating 'If and Only If' (Bi-conditional) Statements: To validate a statement of the form (p if and only if q), we must prove two parts: the necessity () and the sufficiency (). Both directions must be validated independently for the bi-conditional to hold. Visually, this represents a two-way street where traffic (logic) can flow freely in both directions between and .
Validating Statements with 'And' and 'Or': A compound statement joined by 'And' () is validated by showing both and are true. A statement joined by 'Or' () is validated by showing at least one of them is true. For 'Or' statements, we often assume is false and prove must be true. Visually, 'And' is like a series circuit where all switches must be closed, while 'Or' is like a parallel circuit where any one path allows the current to flow.
Quantifiers and Validity: Statements containing 'For every' (Universal Quantifier, ) require a general proof that covers every element in the domain. Statements containing 'There exists' (Existential Quantifier, ) only require finding or constructing one specific element that satisfies the condition. Visually, refers to the entire set (the whole circle), while refers to at least one specific dot within that circle.
📐Formulae
💡Examples
Problem 1:
Check the validity of the statement: 'If is an integer and is even, then is even' using the method of contrapositive.
Solution:
- Let be the statement ' is even' and be the statement ' is even'. We need to prove .
- The contrapositive is , which is: 'If is not even (i.e., is odd), then is not even (i.e., is odd)'.
- Assume is true, so is odd. Thus, we can write for some integer .
- Squaring both sides: .
- Simplify: .
- Let . Then , which is the form of an odd integer.
- Since is odd, is true. Thus, is valid.
- Therefore, the original statement is true.
Explanation:
We use the contrapositive method because proving that the square of an odd number is odd is algebraically simpler than working directly with square roots of even numbers. Since the contrapositive is logically equivalent to the original statement, validating it validates the original.
Problem 2:
Prove by contradiction that is an irrational number.
Solution:
- Assume the negation: is rational.
- By definition of rational numbers, , where and are integers with no common factors other than 1 ().
- Squaring both sides: .
- This means is even, so must also be even. Let .
- Substitute into the equation: .
- This means is even, so must also be even.
- If and are both even, they have a common factor of 2. This contradicts our assumption that and have no common factors.
- Therefore, the assumption that is rational is false. Hence, is irrational.
Explanation:
The contradiction method is effective here because it shows that assuming the statement is rational leads to a logical impossibility (the numbers being both coprime and having a common factor), forcing the conclusion that the number must be irrational.