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Mathematical Reasoning - Implications (If-then, If and only if)

Grade 11CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Conditional Statement (Implication): A statement formed by joining two simple statements pp and qq with the connective 'if...then' is called a conditional statement, denoted by pqp \rightarrow q. In this structure, pp is called the antecedent (or hypothesis) and qq is the consequent (or conclusion). Visually, this represents a directed flow of logic from one condition to its result.

Truth Values of pqp \rightarrow q: The implication pqp \rightarrow q is considered False only when the antecedent pp is True and the consequent qq is False. In all other cases—when pp is False (regardless of qq) or when both are True—the statement is True. Imagine a promise: the promise is only broken if the condition is met but the result is not delivered.

Converse, Inverse, and Contrapositive: For any conditional statement pqp \rightarrow q, three related statements can be formed: the Converse (qpq \rightarrow p), the Inverse (pq\sim p \rightarrow \sim q), and the Contrapositive (qp\sim q \rightarrow \sim p). It is a fundamental rule of logic that a statement is always logically equivalent to its contrapositive, which can be visualized as two different ways of looking at the same logical boundary.

Biconditional Statement (If and only if): A biconditional statement pqp \leftrightarrow q is the conjunction of two implications: (pq)(qp)(p \rightarrow q) \wedge (q \rightarrow p). It is True only when both pp and qq have the same truth value (both True or both False). Visually, this is represented by a double-headed arrow, indicating that pp and qq are mutually dependent and equivalent in truth.

Negation of an Implication: The negation of pqp \rightarrow q is logically equivalent to pqp \wedge \sim q. This means that the opposite of 'If pp, then qq' is ' pp is true AND qq is false'. Note that the negation of an 'if-then' statement is not another 'if-then' statement, but a conjunction using 'and'.

Equivalent Expressions: The implication pqp \rightarrow q can be expressed in several ways in English: 'pp is sufficient for qq', 'qq is necessary for pp', 'pp only if qq', and 'qq if pp'. Understanding these linguistic variations is key to translating word problems into logical symbols.

📐Formulae

pqp \rightarrow q (Conditional: If pp then qq)

pq(pq)(qp)p \leftrightarrow q \equiv (p \rightarrow q) \wedge (q \rightarrow p) (Biconditional: pp if and only if qq)

(pq)pq\sim(p \rightarrow q) \equiv p \wedge \sim q (Negation of Implication)

(pq)(pq)(qp)\sim(p \leftrightarrow q) \equiv (p \wedge \sim q) \vee (q \wedge \sim p) (Negation of Biconditional)

(pq)(qp)(p \rightarrow q) \equiv (\sim q \rightarrow \sim p) (Contrapositive Equivalence)

💡Examples

Problem 1:

Given the statement: 'If a triangle is equilateral, then it is isosceles', write its converse, inverse, and contrapositive.

Solution:

Let pp: 'A triangle is equilateral' and qq: 'A triangle is isosceles'.

  1. Converse (qpq \rightarrow p): 'If a triangle is isosceles, then it is equilateral.'
  2. Inverse (pq\sim p \rightarrow \sim q): 'If a triangle is not equilateral, then it is not isosceles.'
  3. Contrapositive (qp\sim q \rightarrow \sim p): 'If a triangle is not isosceles, then it is not equilateral.'

Explanation:

We identify the hypothesis pp and conclusion qq, then apply the standard logical transformations. Note that while the original statement and contrapositive are true, the converse and inverse are false in this specific geometric case.

Problem 2:

Determine the truth value of the biconditional statement: '4+4=84 + 4 = 8 if and only if 2×5=112 \times 5 = 11'.

Solution:

Let pp: '4+4=84 + 4 = 8' and qq: '2×5=112 \times 5 = 11'.

  1. The truth value of pp is True (TT) because 4+44 + 4 is indeed 88.
  2. The truth value of qq is False (FF) because 2×5=102 \times 5 = 10, not 1111.
  3. A biconditional pqp \leftrightarrow q is True only when both pp and qq have the same truth value.
  4. Since one is TT and the other is FF, the compound statement pqp \leftrightarrow q is False (FF).

Explanation:

The biconditional connective \leftrightarrow acts as an equivalence operator; if the two sides do not match in truth, the entire statement fails.