Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
A quadratic equation with real coefficients is expressed in the standard form , where and . Visually, this equation represents a parabola that opens upwards if and downwards if .
The Discriminant, denoted as , determines the nature of the roots. When , the parabola does not intersect or touch the x-axis at any point, indicating that the roots are not real but complex numbers.
For a quadratic equation with real coefficients, if the discriminant is negative, the roots are complex and always occur in conjugate pairs. This means if one root is , then the other root must be .
The Fundamental Theorem of Algebra states that a polynomial equation of degree has exactly roots in the complex number system. For quadratic equations (), there are exactly two roots, which may be real and distinct, real and equal, or complex conjugates.
When solving with , we introduce the imaginary unit . The square root of the negative discriminant is expressed as or , allowing us to find solutions in the complex plane.
Graphically, the complex roots of can be visualized as points in the Argand plane. Because they are conjugates (), they are reflections of each other across the real (horizontal) axis.
📐Formulae
Standard Form:
Discriminant:
Quadratic Formula:
Roots when :
Sum of roots ():
Product of roots ():
💡Examples
Problem 1:
Solve the quadratic equation over the set of complex numbers.
Solution:
Step 1: Identify coefficients: . \nStep 2: Calculate the discriminant . \nStep 3: Since , the roots are complex. Use the formula . \nStep 4: Substitute values: . \nStep 5: The roots are and .
Explanation:
We use the quadratic formula for case where the discriminant is negative. The negative sign under the square root is replaced by the imaginary unit outside the radical.
Problem 2:
Solve .
Solution:
Step 1: Identify coefficients: . \nStep 2: Calculate . \nStep 3: Apply the quadratic formula for complex roots: . \nStep 4: Simplify using : .
Explanation:
Even with irrational coefficients, the process remains the same. Since is negative, the roots are a pair of complex conjugates.