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Complex Numbers and Quadratic Equations - Complex Numbers

Grade 11CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Imaginary Unit ii: The concept of complex numbers begins with the imaginary unit ii, defined as i=1i = \sqrt{-1}, such that i2=1i^2 = -1. This allows us to solve equations like x2+1=0x^2 + 1 = 0, which have no real solutions. Visually, while real numbers exist on a single horizontal line, the introduction of ii adds a second dimension (the vertical axis) to our number system.

Complex Number Definition: A complex number zz is expressed in the form a+iba + ib, where aa and bb are real numbers. Here, aa is the real part, denoted by Re(z)Re(z), and bb is the imaginary part, denoted by Im(z)Im(z). If a=0a = 0, the number is 'purely imaginary'; if b=0b = 0, the number is 'purely real'.

The Argand Plane: A complex number z=a+ibz = a + ib is represented visually as a point P(a,b)P(a, b) on a 2D coordinate plane called the Argand Plane (or Complex Plane). The horizontal x-axis is known as the 'Real Axis', and the vertical y-axis is the 'Imaginary Axis'. Every complex number corresponds to a unique point in this plane, and vice-versa.

Modulus of a Complex Number: The modulus of z=a+ibz = a + ib, denoted by z|z|, is the non-negative real number a2+b2\sqrt{a^2 + b^2}. Geometrically, z|z| represents the distance of the point zz from the origin O(0,0)O(0, 0) in the Argand plane. It can be visualized as the length of the vector connecting the origin to the point (a,b)(a, b).

Conjugate of a Complex Number: The conjugate of z=a+ibz = a + ib is denoted by zˉ\bar{z} and is defined as aiba - ib. Visually, zˉ\bar{z} is the mirror image of the point zz with respect to the Real Axis. For example, if zz is in the first quadrant at (a,b)(a, b), its conjugate zˉ\bar{z} will be directly below it in the fourth quadrant at (a,b)(a, -b).

Equality and Algebra: Two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id are equal if and only if a=ca = c and b=db = d. For addition and subtraction, we combine the real parts and imaginary parts separately. For multiplication, we use the distributive property (FOIL) and replace i2i^2 with 1-1. Division is performed by multiplying both the numerator and denominator by the conjugate of the denominator to make the denominator a real number.

Powers of ii: The powers of ii follow a cyclic pattern of four: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, and i4=1i^4 = 1. For any integer nn, i4n=1i^{4n} = 1, i4n+1=ii^{4n+1} = i, i4n+2=1i^{4n+2} = -1, and i4n+3=ii^{4n+3} = -i. This cycle allows us to simplify any high power of ii by finding the remainder when the exponent is divided by 4.

Square Roots of Negative Real Numbers: For any positive real number aa, the square root of a-a is expressed as a=1a=ia\sqrt{-a} = \sqrt{-1} \cdot \sqrt{a} = i\sqrt{a}. In quadratic equations ax2+bx+c=0ax^2 + bx + c = 0, if the discriminant D=b24ac<0D = b^2 - 4ac < 0, the roots are complex and given by x=b±i4acb22ax = \frac{-b \pm i\sqrt{4ac - b^2}}{2a}.

📐Formulae

i=1,i2=1,i3=i,i4=1i = \sqrt{-1}, i^2 = -1, i^3 = -i, i^4 = 1

z=a+ibz = a + ib

zˉ=aib\bar{z} = a - ib

z=a2+b2|z| = \sqrt{a^2 + b^2}

zzˉ=z2z \bar{z} = |z|^2

z1=zˉz2=aiba2+b2z^{-1} = \frac{\bar{z}}{|z|^2} = \frac{a - ib}{a^2 + b^2}

(a+ib)+(c+id)=(a+c)+i(b+d)(a + ib) + (c + id) = (a + c) + i(b + d)

(a+ib)(c+id)=(acbd)+i(ad+bc)(a + ib)(c + id) = (ac - bd) + i(ad + bc)

For ax2+bx+c=0, if D<0,x=b±iD2a\text{For } ax^2 + bx + c = 0, \text{ if } D < 0, x = \frac{-b \pm i\sqrt{|D|}}{2a}

💡Examples

Problem 1:

Express the following in the form a+iba + ib: 5+i21i2\frac{5 + i\sqrt{2}}{1 - i\sqrt{2}}

Solution:

To remove the imaginary part from the denominator, multiply the numerator and denominator by the conjugate of the denominator, which is 1+i21 + i\sqrt{2}.

Step 1: Multiplication z=(5+i2)(1+i2)(1i2)(1+i2)z = \frac{(5 + i\sqrt{2})(1 + i\sqrt{2})}{(1 - i\sqrt{2})(1 + i\sqrt{2})}

Step 2: Expand the numerator (5)(1)+(5)(i2)+(i2)(1)+(i2)(i2)(5)(1) + (5)(i\sqrt{2}) + (i\sqrt{2})(1) + (i\sqrt{2})(i\sqrt{2}) =5+5i2+i2+2i2= 5 + 5i\sqrt{2} + i\sqrt{2} + 2i^2 =5+6i22(since i2=1)= 5 + 6i\sqrt{2} - 2 \quad (\text{since } i^2 = -1) =3+6i2= 3 + 6i\sqrt{2}

Step 3: Expand the denominator using (xy)(x+y)=x2y2(x-y)(x+y) = x^2 - y^2 12(i2)2=1(2i2)=1(2)=1+2=31^2 - (i\sqrt{2})^2 = 1 - (2i^2) = 1 - (-2) = 1 + 2 = 3

Step 4: Final division z=3+6i23=33+i623=1+2i2z = \frac{3 + 6i\sqrt{2}}{3} = \frac{3}{3} + i\frac{6\sqrt{2}}{3} = 1 + 2i\sqrt{2}

Result: 1+i(22)1 + i(2\sqrt{2})

Explanation:

The standard technique to simplify a complex fraction is 'rationalizing' the denominator using its complex conjugate. This utilizes the property zzˉ=z2z\bar{z} = |z|^2, which always results in a real number.

Problem 2:

Solve the quadratic equation: 2x2+x+1=02x^2 + x + 1 = 0

Solution:

Step 1: Identify coefficients a=2,b=1,c=1a = 2, b = 1, c = 1

Step 2: Calculate the discriminant DD D=b24ac=(1)24(2)(1)=18=7D = b^2 - 4ac = (1)^2 - 4(2)(1) = 1 - 8 = -7

Step 3: Since D<0D < 0, the roots are complex numbers. Using the quadratic formula: x=b±D2ax = \frac{-b \pm \sqrt{D}}{2a} x=1±72(2)x = \frac{-1 \pm \sqrt{-7}}{2(2)}

Step 4: Simplify 7\sqrt{-7} as i7i\sqrt{7} x=1±i74x = \frac{-1 \pm i\sqrt{7}}{4}

Result: x=14+i74x = -\frac{1}{4} + i\frac{\sqrt{7}}{4} and x=14i74x = -\frac{1}{4} - i\frac{\sqrt{7}}{4}

Explanation:

When the discriminant of a quadratic equation is negative, we use the imaginary unit ii to express the square root of the negative number. The roots of a quadratic equation with real coefficients always occur in conjugate pairs.