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Complex Numbers and Quadratic Equations - Algebra of Complex Numbers

Grade 11CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Introduction to the Imaginary Unit ii: The symbol ii is defined as 1\sqrt{-1}, such that i2=1i^2 = -1. Visually, if the real number line is a horizontal axis, multiplying a number by ii can be seen as a 9090^\circ counter-clockwise rotation into a second dimension, called the imaginary axis.

Complex Numbers in Standard Form: A complex number zz is expressed in the form a+bia + bi, where aa is the real part Re(z)\text{Re}(z) and bb is the imaginary part Im(z)\text{Im}(z). Geometrically, this represents a point (a,b)(a, b) on a 2D coordinate system known as the Argand Plane or Complex Plane, where the x-axis is the Real axis and the y-axis is the Imaginary axis.

Equality of Complex Numbers: Two complex numbers z1=a+biz_1 = a + bi and z2=c+diz_2 = c + di are equal if and only if their corresponding real and imaginary parts are identical, meaning a=ca = c and b=db = d. This implies that a single equation involving complex numbers is actually a system of two real equations.

Addition and Subtraction: To add or subtract complex numbers, we combine the real parts and imaginary parts separately. Visually, adding two complex numbers z1z_1 and z2z_2 follows the Parallelogram Law of Vector Addition, where the resultant sum is the diagonal of the parallelogram formed by the vectors representing z1z_1 and z2z_2 from the origin.

Multiplication and Rotations: Multiplication of (a+bi)(a + bi) and (c+di)(c + di) is performed using the distributive law (FOIL), replacing i2i^2 with 1-1. Conceptually, multiplying complex numbers involves scaling their distances from the origin and adding their angles relative to the positive real axis.

The Conjugate of a Complex Number: The conjugate of z=a+biz = a + bi, denoted as zˉ\bar{z}, is abia - bi. On the Argand plane, zˉ\bar{z} is the mirror image or reflection of zz across the horizontal Real axis.

Modulus of a Complex Number: The modulus z|z| of z=a+biz = a + bi is defined as a2+b2\sqrt{a^2 + b^2}. Visually, this represents the absolute distance of the point (a,b)(a, b) from the origin (0,0)(0, 0), following the Pythagorean theorem where z|z| is the length of the hypotenuse.

Powers of ii: The powers of ii follow a repeating cyclic pattern of four values: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, and i4=1i^4 = 1. For any integer nn, ini^n can be simplified by finding the remainder when nn is divided by 4.

📐Formulae

i=1,i2=1,i3=i,i4=1i = \sqrt{-1}, i^2 = -1, i^3 = -i, i^4 = 1

z=a+biz = a + bi

(a+bi)±(c+di)=(a±c)+i(b±d)(a + bi) \pm (c + di) = (a \pm c) + i(b \pm d)

(a+bi)(c+di)=(acbd)+i(ad+bc)(a + bi)(c + di) = (ac - bd) + i(ad + bc)

zˉ=abi\bar{z} = a - bi

z=a2+b2|z| = \sqrt{a^2 + b^2}

zzˉ=z2z \cdot \bar{z} = |z|^2

z1=zˉz2=abia2+b2z^{-1} = \frac{\bar{z}}{|z|^2} = \frac{a - bi}{a^2 + b^2}

💡Examples

Problem 1:

Simplify the expression and express in a+bia + bi form: (3+4i)(2i)(3 + 4i)(2 - i)

Solution:

Step 1: Use the distributive property (FOIL): (3)(2)+(3)(i)+(4i)(2)+(4i)(i)(3)(2) + (3)(-i) + (4i)(2) + (4i)(-i) Step 2: Multiply the terms: 63i+8i4i26 - 3i + 8i - 4i^2 Step 3: Substitute i2=1i^2 = -1: 6+5i4(1)6 + 5i - 4(-1) Step 4: Combine real and imaginary parts: 6+5i+4=10+5i6 + 5i + 4 = 10 + 5i Final Answer: 10+5i10 + 5i

Explanation:

To multiply complex numbers, treat them as binomials. The key step is substituting 1-1 for i2i^2 to convert the imaginary product back into a real number.

Problem 2:

Find the multiplicative inverse of z=34iz = 3 - 4i.

Solution:

Step 1: Use the formula for multiplicative inverse z1=zˉz2z^{-1} = \frac{\bar{z}}{|z|^2}. Step 2: Find the conjugate zˉ\bar{z}: zˉ=3+4i\bar{z} = 3 + 4i Step 3: Calculate the square of the modulus z2|z|^2: z2=32+(4)2=9+16=25|z|^2 = 3^2 + (-4)^2 = 9 + 16 = 25 Step 4: Divide the conjugate by the squared modulus: z1=3+4i25=325+425iz^{-1} = \frac{3 + 4i}{25} = \frac{3}{25} + \frac{4}{25}i Final Answer: 325+425i\frac{3}{25} + \frac{4}{25}i

Explanation:

The multiplicative inverse is the reciprocal of the number. To rationalize the denominator, we multiply the numerator and denominator by the conjugate of the original complex number.