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Algebra - Quadratic Equations in one variable

Grade 10ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Standard Form: A quadratic equation in one variable xx is represented as ax2+bx+c=0ax^2 + bx + c = 0, where a,b,ca, b, c are real numbers and a0a \neq 0. Visually, the graph of a quadratic equation is a parabola. If a>0a > 0, the parabola opens upwards (like a U-shape); if a<0a < 0, it opens downwards (like an inverted U).

Roots of the Equation: The values of xx that satisfy the equation are called its roots or zeros. Geometrically, these roots represent the x-intercepts of the parabola, where the graph crosses or touches the horizontal x-axis.

Nature of Roots (The Discriminant): The value D=b24acD = b^2 - 4ac is called the discriminant. It determines the nature of the roots without solving the equation. Visually: if D>0D > 0, the parabola cuts the x-axis at two distinct points (real and unequal roots); if D=0D = 0, the vertex of the parabola touches the x-axis at exactly one point (real and equal roots); if D<0D < 0, the parabola stays entirely above or below the x-axis and never touches it (imaginary roots).

Solving by Factorization: This method involves rewriting the quadratic expression ax2+bx+cax^2 + bx + c as a product of two linear factors (px+q)(rx+s)=0(px + q)(rx + s) = 0. We usually split the middle term bxbx into two terms such that their sum is bb and their product is acac. Once factored, we apply the Zero Product Rule: if A×B=0A \times B = 0, then A=0A = 0 or B=0B = 0.

Quadratic Formula (Sridharacharya's Rule): For equations where factorization is difficult, the roots can be calculated using the formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. This formula provides a direct algebraic path to find both values of xx.

Relation between Roots and Coefficients: If α\alpha and β\beta are the two roots of ax2+bx+c=0ax^2 + bx + c = 0, then the sum of the roots is given by α+β=ba\alpha + \beta = -\frac{b}{a} and the product of the roots is given by αβ=ca\alpha\beta = \frac{c}{a}. These relationships allow us to form a quadratic equation if the roots are known using the structure x2(sum of roots)x+(product of roots)=0x^2 - (\text{sum of roots})x + (\text{product of roots}) = 0.

Equations Reducible to Quadratic Form: Some equations are not quadratic initially but can be converted into one through substitution. For example, an equation like x45x2+4=0x^4 - 5x^2 + 4 = 0 can be treated as a quadratic by letting x2=yx^2 = y, resulting in y25y+4=0y^2 - 5y + 4 = 0.

📐Formulae

Standard Form: ax2+bx+c=0ax^2 + bx + c = 0

Discriminant: D=b24acD = b^2 - 4ac

Quadratic Formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Sum of Roots: α+β=ba\alpha + \beta = -\frac{b}{a}

Product of Roots: αβ=ca\alpha \cdot \beta = \frac{c}{a}

Formation of Equation: x2(α+β)x+αβ=0x^2 - (\alpha + \beta)x + \alpha\beta = 0

💡Examples

Problem 1:

Solve the quadratic equation x25x+6=0x^2 - 5x + 6 = 0 using the factorization method.

Solution:

  1. Identify a=1,b=5,c=6a=1, b=-5, c=6.
  2. We need two numbers that multiply to ac=6ac = 6 and add to b=5b = -5. These numbers are 2-2 and 3-3.
  3. Split the middle term: x22x3x+6=0x^2 - 2x - 3x + 6 = 0.
  4. Factor by grouping: x(x2)3(x2)=0x(x - 2) - 3(x - 2) = 0.
  5. Common factor: (x2)(x3)=0(x - 2)(x - 3) = 0.
  6. Set each factor to zero: x2=0x=2x - 2 = 0 \Rightarrow x = 2 or x3=0x=3x - 3 = 0 \Rightarrow x = 3.
  7. The roots are 22 and 33.

Explanation:

This approach uses the splitting the middle term technique to find linear factors. Since the product of the factors is zero, at least one of the factors must be zero.

Problem 2:

Find the nature of roots for 2x24x+3=02x^2 - 4x + 3 = 0 and solve if real roots exist.

Solution:

  1. Identify a=2,b=4,c=3a=2, b=-4, c=3.
  2. Calculate the Discriminant: D=b24ac=(4)24(2)(3)=1624=8D = b^2 - 4ac = (-4)^2 - 4(2)(3) = 16 - 24 = -8.
  3. Since D<0D < 0, the roots are not real (they are imaginary/complex).
  4. Since the question asks to solve only if real roots exist, we conclude there are no real solutions for xx.

Explanation:

Checking the discriminant first saves time. A negative discriminant indicates the parabola of the function y=2x24x+3y = 2x^2 - 4x + 3 lies entirely above the x-axis and never intersects it.