Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
The Gradient () measures the steepness and direction of a line. Visually, a positive gradient slopes upwards from left to right, while a negative gradient slopes downwards. A horizontal line has a gradient of , and a vertical line has an undefined gradient.
The -intercept () is the point where the line crosses the vertical -axis. On a graph, this is located at the coordinates . Conversely, the -intercept is where the line crosses the horizontal -axis, found by setting .
The Gradient-Intercept form, , is the most common way to express a straight line. Here, represents the 'rise over run' (vertical change divided by horizontal change) and represents the height at which the line hits the -axis.
The Point-Gradient form, , is used to find the equation of a line when you know its slope and one specific point that it passes through. This is often rearranged into other forms for the final answer.
Parallel lines are lines that maintain a constant distance from each other and never meet. Visually, they have the same slant, which means their gradients are equal ().
Perpendicular lines meet at a right angle (). Their gradients are negative reciprocals of each other (). For example, if one line has a gradient of , the perpendicular line has a gradient of .
The Midpoint is the exact center point between two coordinates and . Visually, it is the 'average' position of the two points on the Cartesian plane.
Distance between two points represents the length of the straight-line segment connecting them. It is calculated by visualizing a right-angled triangle between the points and applying the Pythagorean theorem to the horizontal and vertical distances.
📐Formulae
Gradient:
Gradient-Intercept Form:
Point-Gradient Form:
General Form: (where are usually integers)
Parallel Condition:
Perpendicular Condition: or
Midpoint Formula:
Distance Formula:
💡Examples
Problem 1:
Find the equation of the line passing through the points and . Give your answer in the form .
Solution:
Step 1: Calculate the gradient ():
Step 2: Use the point-gradient formula with point :
Step 3: Expand and simplify:
Explanation:
To find the equation of a line from two points, first determine the rate of change (gradient) between them. Then, substitute one point and the gradient into the linear equation model to solve for the intercept.
Problem 2:
Line has the equation . Find the equation of line which is perpendicular to and passes through the point .
Solution:
Step 1: Identify the gradient of . .
Step 2: Determine the perpendicular gradient ():
Step 3: Use the point and in the point-gradient form:
Step 4: Distribute and simplify:
Explanation:
Since the lines are perpendicular, their gradients must be negative reciprocals. After finding the new gradient, the point-slope formula is used to derive the specific equation for the second line.