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Polynomials - Geometrical Meaning of the Zeroes of a Polynomial

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Definition of a Zero: A real number kk is said to be a zero of a polynomial p(x)p(x) if p(k)=0p(k) = 0. Geometrically, the zeroes of a polynomial p(x)p(x) are the x-coordinates of the points where the graph of y=p(x)y = p(x) intersects the x-axis.

Linear Polynomials: For a linear polynomial ax+bax + b where a0a \neq 0, the graph is a straight line. This line intersects the x-axis at exactly one point, (ba,0)(-\frac{b}{a}, 0). Therefore, every linear polynomial has exactly one zero.

Quadratic Polynomials and Parabolas: The graph of a quadratic polynomial p(x)=ax2+bx+cp(x) = ax^2 + bx + c is a curve called a parabola. If a>0a > 0, the parabola opens upwards (like a 'U'), and if a<0a < 0, the parabola opens downwards (like an inverted 'U').

Number of Zeroes for Quadratics: A quadratic polynomial can have at most 2 zeroes. Visually, there are three cases: the parabola can intersect the x-axis at two distinct points (2 zeroes), touch the x-axis at exactly one point (1 zero/two equal zeroes), or not touch the x-axis at all (no real zeroes).

Cubic Polynomials: A cubic polynomial p(x)=ax3+bx2+cx+dp(x) = ax^3 + bx^2 + cx + d can have at most 3 zeroes. Geometrically, the curve of a cubic polynomial can cross the x-axis at 1, 2, or 3 points. Unlike quadratics, a cubic polynomial always has at least one real zero because the curve must cross the x-axis as it extends from negative infinity to positive infinity.

General Rule for Degree nn: In general, a polynomial p(x)p(x) of degree nn has at most nn zeroes. This means the graph of y=p(x)y = p(x) can intersect the x-axis at a maximum of nn points.

Interpreting Graphs: To find the number of zeroes from a given graph of y=p(x)y = p(x), simply count how many times the curve touches or crosses the horizontal x-axis. Points where the graph crosses the vertical y-axis are ignored as they represent the value p(0)p(0), not the zeroes of the polynomial.

📐Formulae

p(k)=0p(k) = 0 (Condition for kk to be a zero)

x=bax = -\frac{b}{a} (Zero of a linear polynomial ax+bax + b)

y=ax2+bx+cy = ax^2 + bx + c (General form of a quadratic polynomial)

Number of zeroesnNumber\ of\ zeroes \leq n (For a polynomial of degree nn)

💡Examples

Problem 1:

Look at a graph of y=p(x)y = p(x) that crosses the x-axis at (2,0)(-2, 0) and (3,0)(3, 0), and crosses the y-axis at (0,6)(0, -6). Determine the number of zeroes and specify what they are.

Solution:

  1. Identify the points where the graph intersects the x-axis: (2,0)(-2, 0) and (3,0)(3, 0).
  2. The zeroes are the x-coordinates of these intersection points: x=2x = -2 and x=3x = 3.
  3. Ignore the y-intercept (0,6)(0, -6) as it does not indicate a zero.
  4. Total number of zeroes = 22.

Explanation:

The geometric meaning of a zero is the x-coordinate of the point where the graph meets the x-axis. Since there are two such points, the polynomial has two zeroes.

Problem 2:

Given the quadratic polynomial p(x)=x24x+4p(x) = x^2 - 4x + 4, describe the nature of its graph and identify the number of zeroes based on its algebraic form (x2)2(x-2)^2.

Solution:

  1. The polynomial can be rewritten as p(x)=(x2)2p(x) = (x-2)^2.
  2. To find the zeroes, set p(x)=0    (x2)2=0p(x) = 0 \implies (x-2)^2 = 0, which gives x=2,2x = 2, 2.
  3. Since there is only one unique value, the graph (a parabola opening upwards because a=1>0a=1 > 0) touches the x-axis at exactly one point: (2,0)(2, 0).
  4. Number of zeroes = 11 (or two coincident zeroes).

Explanation:

When a quadratic is a perfect square, its parabola just touches the x-axis at a single point, representing one unique real zero.