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Pair of Linear Equations in Two Variables - Graphical Method of Solution

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

General Form: A pair of linear equations in two variables xx and yy is represented as a1x+b1y+c1=0a_1x + b_1y + c_1 = 0 and a2x+b2y+c2=0a_2x + b_2y + c_2 = 0. Visually, each equation represents a straight line on a 2D Cartesian plane.

Geometric Interpretation: The solution to a pair of linear equations is the point of intersection of the two lines. Every point (x,y)(x, y) on a line satisfies the equation of that line; thus, the point where two lines meet satisfies both equations simultaneously.

Intersecting Lines (Unique Solution): If the ratio of the coefficients of xx and yy are not equal, i.e., a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}, the lines will cross at a single point. Visually, these lines form an 'X' shape. Such a system is called 'Consistent'.

Parallel Lines (No Solution): If a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}, the lines have the same slope but different intercepts. Visually, they appear as two parallel lines like railway tracks that never meet. This system is 'Inconsistent'.

Coincident Lines (Infinite Solutions): If a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}, the two equations are essentially multiples of each other. Visually, one line lies directly on top of the other, appearing as a single line. This system is 'Consistent and Dependent'.

The Table of Values: To graph a linear equation, rearrange it to the form y=mx+cy = mx + c. Choose 2 or 3 values for xx (e.g., x=0,1,2x = 0, 1, 2) and calculate the corresponding values of yy. These coordinates (x,y)(x, y) represent the points plotted to draw the straight line.

Consistency vs. Inconsistency: A pair of linear equations is consistent if it has at least one solution (intersecting or coincident lines) and inconsistent if it has no solution (parallel lines).

📐Formulae

General Form: a1x+b1y+c1=0,a2x+b2y+c2=0a_1x + b_1y + c_1 = 0, a_2x + b_2y + c_2 = 0

Unique Solution (Intersecting): a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}

No Solution (Parallel): a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}

Infinitely Many Solutions (Coincident): a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}

💡Examples

Problem 1:

Solve the pair of linear equations graphically: x+y=3x + y = 3 and 2x+5y=122x + 5y = 12.

Solution:

Step 1: Create a table for x+y=3x + y = 3. If x=0,y=3x=0, y=3 (Point A(0,3)A(0,3)). If x=3,y=0x=3, y=0 (Point B(3,0)B(3,0)). Step 2: Create a table for 2x+5y=122x + 5y = 12. If x=1,y=2x=1, y=2 (Point C(1,2)C(1,2)). If x=6,y=0x=6, y=0 (Point D(6,0)D(6,0)). Step 3: Plot points A,BA, B and draw a line. Plot points C,DC, D and draw a second line. Step 4: Observe the intersection. The lines intersect at point (1,2)(1, 2). Therefore, x=1,y=2x = 1, y = 2.

Explanation:

We find two distinct points for each equation by substituting values for xx and solving for yy. By plotting these on a graph, the point where the lines cross (1,2)(1, 2) represents the unique solution that satisfies both equations.

Problem 2:

Determine if the equations x2y=0x - 2y = 0 and 3x+4y=203x + 4y = 20 are consistent and find the solution graphically.

Solution:

Step 1: Check coefficients: a1=1,b1=2,c1=0a_1=1, b_1=-2, c_1=0 and a2=3,b2=4,c2=20a_2=3, b_2=4, c_2=-20. Step 2: Calculate ratios: a1a2=13\frac{a_1}{a_2} = \frac{1}{3} and b1b2=24=12\frac{b_1}{b_2} = \frac{-2}{4} = -\frac{1}{2}. Since 1312\frac{1}{3} \neq -\frac{1}{2}, the system is consistent with a unique solution. Step 3: Plot x2y=0x - 2y = 0: Points (0,0),(4,2)(0,0), (4,2). Step 4: Plot 3x+4y=203x + 4y = 20: Points (0,5),(4,2)(0,5), (4,2). Step 5: The lines intersect at (4,2)(4, 2). The solution is x=4,y=2x=4, y=2.

Explanation:

First, the algebraic ratio test confirms that the lines intersect. Graphing reveals the specific coordinate (4,2)(4, 2) where the lines meet, providing the graphical solution.