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Pair of Linear Equations in Two Variables - Consistency and Inconsistency of Solutions

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

General Form: A pair of linear equations in two variables xx and yy is typically written as a1x+b1y+c1=0a_1x + b_1y + c_1 = 0 and a2x+b2y+c2=0a_2x + b_2y + c_2 = 0. Here, a1,b1,c1,a2,b2,c2a_1, b_1, c_1, a_2, b_2, c_2 are real numbers such that a12+b120a_1^2 + b_1^2 \neq 0 and a22+b220a_2^2 + b_2^2 \neq 0.

Consistent System: A system is called consistent if it has at least one solution. Visually, this is represented by lines that either cross at a single point or overlap entirely, meaning there is at least one set of coordinates (x,y)(x, y) that satisfies both equations.

Inconsistent System: A system is called inconsistent if it has no solution. In a coordinate plane, this is visually depicted as two parallel lines that never intersect, no matter how far they are extended, because they share no common points.

Unique Solution (Intersecting Lines): If the ratio of the coefficients of xx is not equal to the ratio of the coefficients of yy (i.e., a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}), the system is consistent and has exactly one solution. Visually, the two lines intersect at exactly one point on the graph.

Infinitely Many Solutions (Coincident Lines): If the ratios of all coefficients and constants are equal (i.e., a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}), the system is consistent and dependent. Visually, the two equations represent the same line, and one line lies directly on top of the other (coincident).

No Solution (Parallel Lines): If the ratios of the coefficients of xx and yy are equal, but not equal to the ratio of the constants (i.e., a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}), the system is inconsistent. Visually, the lines are parallel and maintain a constant distance from each other.

Dependency: A pair of linear equations which are equivalent (one is a non-zero multiple of the other) is called a dependent pair. A dependent pair of equations is always consistent and is visually seen as a single line on the graph.

📐Formulae

Standard Form: a1x+b1y+c1=0a_1x + b_1y + c_1 = 0 a2x+b2y+c2=0a_2x + b_2y + c_2 = 0

Condition for Unique Solution (Intersecting): a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}

Condition for Infinitely Many Solutions (Coincident): a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}

Condition for No Solution (Parallel): a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}

💡Examples

Problem 1:

Check whether the pair of equations x+3y=6x + 3y = 6 and 2x3y=122x - 3y = 12 is consistent or inconsistent by comparing coefficient ratios.

Solution:

Step 1: Write the equations in standard form: x+3y6=0x + 3y - 6 = 0 (a1=1,b1=3,c1=6a_1 = 1, b_1 = 3, c_1 = -6) 2x3y12=02x - 3y - 12 = 0 (a2=2,b2=3,c2=12a_2 = 2, b_2 = -3, c_2 = -12) Step 2: Calculate the ratios: a1a2=12\frac{a_1}{a_2} = \frac{1}{2} b1b2=33=1\frac{b_1}{b_2} = \frac{3}{-3} = -1 Step 3: Compare ratios: Since 121\frac{1}{2} \neq -1, we have a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}.

Explanation:

Because the ratios of the coefficients of xx and yy are not equal, the lines intersect at a single point. Therefore, the system is consistent and has a unique solution.

Problem 2:

Find the value of kk for which the system of equations x+2y=3x + 2y = 3 and 5x+ky+7=05x + ky + 7 = 0 has no solution.

Solution:

Step 1: Write in standard form: 1x+2y3=01x + 2y - 3 = 0 5x+ky+7=05x + ky + 7 = 0 Step 2: Identify coefficients: a1=1,b1=2,c1=3a_1=1, b_1=2, c_1=-3 and a2=5,b2=k,c2=7a_2=5, b_2=k, c_2=7. Step 3: Apply the condition for no solution: a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}. Step 4: Solve 15=2k\frac{1}{5} = \frac{2}{k}. k=2×5=10k = 2 \times 5 = 10. Step 5: Verify the third ratio: c1c2=37\frac{c_1}{c_2} = \frac{-3}{7}. Since 1537\frac{1}{5} \neq \frac{-3}{7}, the condition holds.

Explanation:

For a system to have no solution, the lines must be parallel. This requires the xx and yy coefficient ratios to be equal while the constant ratio differs. Solving the proportion gives k=10k=10.