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Coordinate Geometry - Section Formula (Internal Division)

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Section Formula is used to find the coordinates of a point P(x,y)P(x, y) that divides a line segment joining two given points A(x1,y1)A(x_1, y_1) and B(x2,y2)B(x_2, y_2) in a specific ratio m1:m2m_1:m_2.

Internal Division occurs when the point PP lies on the line segment ABAB between the points AA and BB. Visually, if you imagine a string stretched from AA to BB, point PP is a knot tied somewhere on that string, dividing it into two pieces of lengths m1m_1 and m2m_2.

The x-coordinate of the dividing point is calculated as the weighted average of the x-coordinates of the endpoints: x=m1x2+m2x1m1+m2x = \frac{m_1x_2 + m_2x_1}{m_1 + m_2}. Similarly, the y-coordinate is y=m1y2+m2y1m1+m2y = \frac{m_1y_2 + m_2y_1}{m_1 + m_2}.

The Midpoint is a special case of the section formula where the ratio m1:m2m_1:m_2 is 1:11:1. Visually, the point MM is located exactly at the center of the segment ABAB, equidistant from both ends.

When calculating the ratio in which a point divides a segment, it is often simpler to assume the ratio is k:1k:1. If the resulting value of kk is positive, it confirms the division is internal.

Points of Trisection are the two points that divide a line segment into three equal parts. To find them, you apply the section formula twice: once with the ratio 1:21:2 and once with the ratio 2:12:1.

The Centroid of a triangle is the point where its three medians intersect. Visually, it is the 'balance point' of the triangle. It divides each median in the ratio 2:12:1 from the vertex to the midpoint of the opposite side.

Coordinate geometry problems involving the X-axis or Y-axis use the visual property that any point on the X-axis has a y-coordinate of 00 (x,0)(x, 0), and any point on the Y-axis has an x-coordinate of 00 (0,y)(0, y).

📐Formulae

Section Formula (Internal): P(x,y)=(m1x2+m2x1m1+m2,m1y2+m2y1m1+m2)P(x, y) = \left( \frac{m_1x_2 + m_2x_1}{m_1 + m_2}, \frac{m_1y_2 + m_2y_1}{m_1 + m_2} \right)

Midpoint Formula: M=(x1+x22,y1+y22)M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)

Ratio k:1k:1 Formula: P(x,y)=(kx2+x1k+1,ky2+y1k+1)P(x, y) = \left( \frac{kx_2 + x_1}{k+1}, \frac{ky_2 + y_1}{k+1} \right)

Centroid of a Triangle: G=(x1+x2+x33,y1+y2+y33)G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)

💡Examples

Problem 1:

Find the coordinates of the point PP which divides the line segment joining the points A(4,3)A(4, -3) and B(8,5)B(8, 5) in the ratio 3:13:1 internally.

Solution:

  1. Identify the given values: (x1,y1)=(4,3)(x_1, y_1) = (4, -3), (x2,y2)=(8,5)(x_2, y_2) = (8, 5), m1=3m_1 = 3, and m2=1m_2 = 1.
  2. Apply the Section Formula for the x-coordinate: x=m1x2+m2x1m1+m2=3(8)+1(4)3+1=24+44=284=7x = \frac{m_1x_2 + m_2x_1}{m_1 + m_2} = \frac{3(8) + 1(4)}{3 + 1} = \frac{24 + 4}{4} = \frac{28}{4} = 7
  3. Apply the Section Formula for the y-coordinate: y=m1y2+m2y1m1+m2=3(5)+1(3)3+1=1534=124=3y = \frac{m_1y_2 + m_2y_1}{m_1 + m_2} = \frac{3(5) + 1(-3)}{3 + 1} = \frac{15 - 3}{4} = \frac{12}{4} = 3
  4. The coordinates of point PP are (7,3)(7, 3).

Explanation:

We use the internal section formula by substituting the endpoints and the given ratio to find the specific coordinates of the point PP located on segment ABAB.

Problem 2:

In what ratio does the point P(4,6)P(-4, 6) divide the line segment joining the points A(6,10)A(-6, 10) and B(3,8)B(3, -8)?

Solution:

  1. Let the ratio be k:1k:1.
  2. Use the x-coordinate formula: x=kx2+x1k+1x = \frac{kx_2 + x_1}{k + 1}.
  3. Substitute the values 4=k(3)+(6)k+1-4 = \frac{k(3) + (-6)}{k + 1}.
  4. Cross-multiply: 4(k+1)=3k6    4k4=3k6-4(k + 1) = 3k - 6 \implies -4k - 4 = 3k - 6.
  5. Rearrange terms: 4k3k=6+4    7k=2-4k - 3k = -6 + 4 \implies -7k = -2.
  6. Solve for kk: k=27k = \frac{2}{7}.
  7. The ratio is 2:72:7.

Explanation:

To find an unknown ratio, we assume it is k:1k:1, set up an equation using one of the coordinates (either x or y), and solve for kk. Since kk is positive, the division is internal.