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Arithmetic Progressions - nth Term of an AP

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Definition of an Arithmetic Progression (AP): An AP is a sequence of numbers in which each term after the first is obtained by adding a fixed number to the preceding term. Imagine a staircase where each step has the exact same height; that height represents the common difference.

First Term and Common Difference: The first term of an AP is denoted by aa. The fixed number added to each term is called the common difference, denoted by dd. If you plot the terms of an AP on a number line, dd is the constant distance between any two adjacent points.

General Form of an AP: The sequence is represented as a,a+d,a+2d,a+3d,a, a+d, a+2d, a+3d, \dots. Visually, this looks like a starting point aa followed by a series of equal 'jumps' of size dd.

The nthn^{th} Term Concept: The nthn^{th} term, denoted as ana_n, is the value located at the nthn^{th} position in the sequence. To reach the nthn^{th} position, you start at aa and perform (n1)(n-1) jumps of size dd.

Direction of the Sequence: If d>0d > 0, the AP is increasing and the values move towards positive infinity. If d<0d < 0, the AP is decreasing and the values move towards negative infinity. If d=0d = 0, the AP is constant, appearing as a horizontal line of identical points on a graph.

Linear Relationship: If we plot the position nn on the x-axis and the value ana_n on the y-axis, all points (n,an)(n, a_n) will lie on a straight line. This shows that the nthn^{th} term is a linear function of nn.

Finite and Infinite APs: An AP that has a limited number of terms is called a finite AP and has a last term (ll). An AP that goes on forever is called an infinite AP, represented with an ellipsis (\dots) at the end.

📐Formulae

General term (nthn^{th} term) of an AP: an=a+(n1)da_n = a + (n - 1)d

Common difference: d=akak1d = a_k - a_{k-1} or d=a2a1d = a_2 - a_1

Last term of a finite AP: l=a+(n1)dl = a + (n - 1)d

Position of a term: n=anad+1n = \frac{a_n - a}{d} + 1

💡Examples

Problem 1:

Find the 15th15^{th} term of the AP: 3,8,13,18,3, 8, 13, 18, \dots

Solution:

Step 1: Identify the first term aa and common difference dd. Here, a=3a = 3 and d=83=5d = 8 - 3 = 5. Step 2: Use the formula for the nthn^{th} term: an=a+(n1)da_n = a + (n - 1)d. Step 3: Substitute n=15n = 15, a=3a = 3, and d=5d = 5 into the formula: a15=3+(151)×5a_{15} = 3 + (15 - 1) \times 5 a15=3+(14)×5a_{15} = 3 + (14) \times 5 a15=3+70=73a_{15} = 3 + 70 = 73 Therefore, the 15th15^{th} term is 7373.

Explanation:

To find a specific term in a sequence, we identify the starting point and the growth rate (common difference), then apply the general term formula.

Problem 2:

Which term of the AP: 21,18,15,21, 18, 15, \dots is 81-81?

Solution:

Step 1: Identify the given values: a=21a = 21, d=1821=3d = 18 - 21 = -3, and an=81a_n = -81. Step 2: Use the formula an=a+(n1)da_n = a + (n - 1)d and solve for nn: 81=21+(n1)(3)-81 = 21 + (n - 1)(-3) Step 3: Subtract 2121 from both sides: 8121=(n1)(3)-81 - 21 = (n - 1)(-3) 102=(n1)(3)-102 = (n - 1)(-3) Step 4: Divide by 3-3: 1023=n1\frac{-102}{-3} = n - 1 34=n134 = n - 1 Step 5: Add 11 to both sides: n=35n = 35 So, the 35th35^{th} term is 81-81.

Explanation:

When the value of the term is known but its position is not, we treat nn as the unknown variable and solve the linear equation.